Question

我正试图从kickstarter网站获取有关每个项目每类奖励的支持者数量的数据。我的输入是一个网址列表。

我遇到了很多问题：

我无法从txt文件中加载网址，但只有当列表位于python中时，我的代码才有效。

我试图抓取的数据示例是这样的（实际上下面是我在下面的代码中从2个链接中抓取的一段数据）：

..... ..... ，承诺CA $ 500或以上约€325 ，承诺2,500美元或以上约€1,625 ， 5个支持者， 2个支持者， ........ .......
我需要在每个项目的CSV文件的行中写上面显示的结果。因此，CSV文件的第一个单元格将是项目链接（或标题，如果使用beautifulsoup进行删除）;第二列应该是一系列值，其中包含每个商品的支持者数量。使用上述数据的示例：

"project link" , "pledge__backer-count" 5 backers , "pledge__amount" $500

我正在努力处理来自网址列表的代码部分。第一部分是从网络上的一个例子中复制而来的，效果很好。在此先感谢您的帮助，我的论文确实需要这个。＆＃34;＆＃34;＆＃34;

from requests import get
from requests.exceptions import RequestException
from contextlib import closing
from bs4 import BeautifulSoup
import re

def simple_get(url):
    """
    Attempts to get the content at `url` by making an HTTP GET request.
    If the content-type of response is some kind of HTML/XML, return the
    text content, otherwise return None
    """
    try:
        with closing(get(url, stream=True)) as resp:
            if is_good_response(resp):
                return resp.content
            else:
                return None

    except RequestException as e:
        log_error('Error during requests to {0} : {1}'.format(url, str(e)))
        return None

def is_good_response(resp):
    """
    Returns true if the response seems to be HTML, false otherwise
    """
    content_type = resp.headers['Content-Type'].lower()
    return (resp.status_code == 200 
            and content_type is not None 
            and content_type.find('html') > -1)

def log_error(e):
    """
    It is always a good idea to log errors. 
    This function just prints them, but you can
    make it do anything.
    """
    print(e)



urls=['https://www.kickstarter.com/projects/socialismmovie/socialism-an-american-story?ref=home_potd','https://www.kickstarter.com/projects/1653847368/the-cuban-a-film-about-the-power-of-music-over-alz?ref=home_new_and_noteworthy']


for url in urls:
        Project_raw=simple_get(url)
        Project_bs4= BeautifulSoup(Project_raw, 'lxml')

        Backers_offers=Project_bs4.find_all("h2", class_="pledge__amount")
        Backers_per_offer=Project_bs4.find_all("span", class_="pledge__backer-count")
        Offers_plus_Backers=Backers_offers+Backers_per_offer

        print(Offers_plus_Backers)

使用beautifulsoup在Kickstarter上刮刮多个网址

0 个答案: