Question

我为我正在制作的节目制作了一个函数，这是一个数学游戏，你必须输入答案，如果答案是对的，你就赢了。我认为游戏很简单，但出于某种原因，无论何时输入答案，程序都会说错了，即使答案是对的。

def gameChoice():
    print("what game do you want to play? A math game")
    game_choice = input(">>")
    if game_choice == 'math game':
        number1 = random.randint(1, 30)
        number2 = random.randint(1, 30)
        answer = (number1 + number2)
        print("%d + %d = %d" %(number1, number2, answer))
        player_answer = input(">> ")
        if player_answer == answer:
            print("congrats, you got it right")

        else:
            print("sorry, try again")

Answer 1

代码：

player_answer is a string

和

answer is an int

这使得2永远不会相互试图放

player_answer = int(input(">> "))

这会使输入自动为integer

Answer 2

而不是int，你可以使用literal_eval（来自内置的ast）。如果你想在将来支持浮点数，那将允许float或int。如果用户输入字符串或只是按Enter键，您还需要一些异常处理。

然后，您将要循环，直到用户正确为止。一个可能的解决方案是：

import random
from ast import literal_eval

def gameChoice():
    print("what game do you want to play? A math game")
    game_choice = input(">>")
    if game_choice == 'math game':
        number1 = random.randint(1, 30)
        number2 = random.randint(1, 30)
        answer = (number1 + number2)

        while True:
            print("%d + %d = %d" % (number1, number2, answer))
            try:
                player_answer = literal_eval(input(">> "))
            except ValueError:
                print('Please enter a number for the answer')
            except SyntaxError:
                print('Please enter an answer')
            else:
                if player_answer == answer:
                    break
                else:
                    print("sorry, try again")

        print("congrats, you got it right")

数学游戏不起作用

2 个答案: