Question

这是我正在处理的代码。我正在为我的移动设备创建API。

<?php

$property_id=$_GET['property_id'];

$res_image=mysql_query("select * 
                        from fak_property_image 
                        where property_id='".$property_id."'");
$i=0;
while($row2=mysql_fetch_array($res_image)){

    // $status[$i]['property_id']=$row2['property_id'];
    // $status[$i]['image']=$row2['image'];
    $status[$i]['path']=$row2['path'];
    $i++;   
 }
echo json_encode( $status );exit;

?>

输出正在跟随

[
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0008.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0009.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0013.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0015.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0016.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0074.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0210.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0211.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1400.1525441844.JPG"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1903.1525441844.jpg"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1904.1525441844.jpg"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1905.1525441844.jpg"},
{"path":"http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1906.1525441844.jpg"}
]

但我的要求是像这样显示输出

[
    {
    "path":
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0008.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0009.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0013.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0015.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0016.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0074.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0210.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_0211.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1400.1525441844.JPG",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1903.1525441844.jpg",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1904.1525441844.jpg",:
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1905.1525441844.jpg",
        "http:\/\/grandthecompany.com\/admin\/uploads\/IMG_1906.1525441844.jpg"
    }
]

我试图使用mysql_fetch_all获取所有数据，但它无法正常工作。请帮忙。

由于

Answer 1

尝试以下方法：

$status['path'][] = $row2['path'];

而不是：

$status[$i]['path']=$row2['path'];

但你肯定应该使用PDO，除了这个代码容易受到SQL注入。

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1 个答案: