Question

我是javascript和json对象的新手。我正在处理一个数组，其中每个元素如下所示：

 input = { 
      clgid: 135,
      careerlevelid: 10000130,
      metricname: 'joiners',
      monthnames: '201810,201811,201812,20184,20185,....',
      metricvalue: '18.00,0.00,7.00,15.00,0.00,0.00,....' 
      }

monthanames - 可以是1到24之间的任何

metricvalue - 是该月份名的相应值

我想要一个如下的输出：

output = { 
  clgid: 135,
  careerlevelid: 10000130,
  metricname: 'joiners',
   201810: 18.00,
  201811: 0.00,
  201812: 7.00,
  201804: 15.00,
  201805: 0.00,

}

Iam尝试使用for循环（）和TSMap（https://www.npmjs.com/package/typescript-map）来做这件事，但不知怎的，我无法获得所需的输出。

Answer 1

您可以使用Map创建新属性。

let input = { 
      clgid: 135,
      careerlevelid: 10000130,
      metricname: 'joiners',
      monthnames: '201810,201811,201812,20184,20185',
      metricvalue: '18.00,0.00,7.00,15.00,0.00,0.00' 
      };
      
let months = input.monthnames.split(',');
let values = input.metricvalue.split(',');
input.metricname = [input.metricname, ...months.map((month, i) => month+':'+values[i])];



console.log(input);

Answer 2

使用destructuring with rest获取monthnames，metricvalue和base（其他媒体资源）。

String.split() monthnames和metricvalue到数组。

使用Array.map()来迭代months。从values获取相应的值，然后创建一个对象。

使用`Object.assign()和array spread与base结合使用。

注1：月份将按其键的数值排序。

注2：将值转换为数字会删除冗余小数点。

＆＃13;

const input = {
  clgid: 135,
  careerlevelid: 10000130,
  metricname: 'joiners',
  monthnames: '201810,201811,201812,20184,20185',
  metricvalue: '18.00,0.00,7.00,15.00,0.00,0.00'
};

const reformatMonthes = (obj) => {
  const { monthnames, metricvalue, ...base } = input;
  const months = monthnames.split(',');
  const values = metricvalue.split(',');
  
  return Object.assign(
    base,
    ...months.map((m, i) => ({
      [m]: +values[i]
    }))
  );
};
console.log(reformatMonthes(input));

＆＃13;

为了保留订单，最好使用月份对象数组：

＆＃13;

const input = {
  clgid: 135,
  careerlevelid: 10000130,
  metricname: 'joiners',
  monthnames: '201810,201811,201812,20184,20185',
  metricvalue: '18.00,0.00,7.00,15.00,0.00,0.00'
};

const reformatMonthes = (obj) => {
  const { monthnames, metricvalue, ...base } = input;
  const months = monthnames.split(',');
  const values = metricvalue.split(',');
  
  return {
    ...base,
    months: months.map((m, i) => ({
      [m]: +values[i]
    }))
  };
};
console.log(reformatMonthes(input));

＆＃13;

Answer 3

试试这个：

＆＃13;

var jsonObj = {
	"clgid": 135,
	"careerlevelid": 10000130,
	"metricname": "joiners",
	"monthnames": "201810,201811,201812,20184,20185",
	"metricvalue": "18.00,0.00,7.00,15.00,0.00"
};

// Split month names string to convert it into an array.
var monthnames = jsonObj.monthnames.split(',');

// Split metric value string to convert it into an array.
var metricvalue = jsonObj.metricvalue.split(',');

// delete monthnames property from an jsonObj.
delete jsonObj.monthnames;

// delete metricvalue property from an jsonObj.
delete jsonObj.metricvalue;

// iterate monthnames to assign the array elements as key in jsonObj.
for (var i in monthnames) {
    jsonObj[monthnames[i]] = metricvalue[i];
}

// Output
console.log(jsonObj);

＆＃13;

javascript：隐式匹配两个javascript对象并创建一个对象

3 个答案: