oracle选择具有相同columng但不同于其他值的值

Question

我在表中有这个值：

我需要选择相同的ID，其中VALUE都是W： ID ; 示例ID：534103

Answer 1

使用id：

not exists

但是，您也可以使用select distinct t.id from table t where not exists (select 1 from table where id = t.id and value != 'W');

GROUP BY

修改

select id
from table t
group by id
having sum(case when value != 'W' then 1 else 0 end) = 0;

Answer 2

您可以使用聚合：

select id
from t
group by id
having min(value) = max(value) and min(value) = 'W';

Answer 3

您可以使用HAVING子句：

SELECT ID
FROM   your_table
GROUP BY ID
HAVING COUNT( CASE value WHEN 'W' THEN 1 END ) = COUNT(*)

或：

SELECT ID
FROM   your_table
GROUP BY ID
HAVING COUNT( CASE WHEN value = 'W' THEN NULL ELSE 1 END ) = 0

或者，如果您想要匹配的组的所有行：

SELECT *
FROM   (
  SELECT t.*,
         COUNT( CASE WHEN value < > 'W' THEN 1 END ) OVER ( PARTITION BY id )
           AS Num_Non_W
  FROM   your_table
)
WHERE  Num_Non_W = 0