Question

所以我目前正在尝试反序列化JSON API。我使用的代码与我成功用于其他API的代码相同。但每个变量只返回0.

    public class RootObject
{
    public int lat { get; set; }
    public int lon { get; set; }
    public DateTime date_iso { get; set; }
    public int date { get; set; }
    public double value { get; set; }
}

public class UVGetter
{
    public static async Task<RootObject> UVApiProxy(double lat, double lon)
    {
        var Timestamp = new DateTimeOffset(DateTime.UtcNow).ToUnixTimeSeconds();

        var http = new HttpClient();
        string WeatherApiKey = "secret";
        var url = String.Format($"https://api.openweathermap.org/data/2.5/uvi/history?appid=" + WeatherApiKey + "&lat=" + Math.Round(lat) + "&lon=" + Math.Round(lon) + "&start=" + Timestamp + "&end=" + Timestamp);
        var response = await http.GetAsync(url);
        var result = await response.Content.ReadAsStringAsync();
        var serializer = new DataContractJsonSerializer(typeof(RootObject));

        var ms = new MemoryStream(Encoding.UTF8.GetBytes(result));
        var uvdata = (RootObject)serializer.ReadObject(ms);
        Agara.Program.WeatherApiCalls++;
        Console.WriteLine(uvdata.lat + "\n" + uvdata.lon + "\n" + uvdata.date_iso.ToString() + "\n" + uvdata.date + "\n" + uvdata.value);
        return uvdata;
    }
}

结果如下所示

[{"lat":54,"lon":9,"date_iso":"2018-05-08T12:00:00Z","date":1525780800,"value":5.62}]

变量（例如uvdata.lat）只包含零，尽管API信息应该存储在那些中。

Answer 1

JSON不包含RootObject，它是RootObject的数组。所以：

var serializer = new DataContractJsonSerializer(typeof(RootObject[]))
// ...
var uvdata = (RootObject[])serializer.ReadObject(ms);

或者，使用Newtonsoft.Json：

var uvData = JsonConvert.DeserializeObject<RootObject[]>(result);

您也可以反序列化为List<RootObject>而不是数组。

如果要保留前导零，请将这些属性反序列化为字符串，因为整数没有这个概念，所以：

public class RootObject
{
    public string lat { get; set; }
    public string lon { get; set; }
    public DateTime date_iso { get; set; }
    public int date { get; set; }
    public double value { get; set; }
}

Answer 2

您的json字符串是一个数组而不是单个对象，因此您应该反序列化为数组。您也可以使用Newtonsoft.Json（即使它很容易使用），只需复制json字符串并在VisualStudio中轻松创建android { compileSdkVersion 25 buildToolsVersion '26.0.2' defaultConfig { applicationId "com.example.app" minSdkVersion 15 targetSdkVersion 24 versionCode 9 versionName "1.0" multiDexEnabled true //Add this testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner" } buildTypes { release { shrinkResources true minifyEnabled true proguardFiles getDefaultProguardFile('proguard-android-optimize.txt'), 'proguard-rules.pro' } } }

编辑 - ＆gt; PasteSpecial - ＆gt;将JSON粘贴为类

class

无法在C＃中反序列化JSON响应

2 个答案: