以下MySQL查询在PHP中运行且没有错误,但结果集为空。直接将查询字符串输出到文件并使用'source [filename]'在MySQL客户端中运行查询会返回几行结果,如预期的那样。
是否存在会导致此查询无法与PHP一起使用的内容? categorylinks.cl_to和smw_spec2.value_string都是varbinary(255)。显示create table表示engine = InnoDB,默认charset = binary。
我尝试过的事情没有成功:
$sql = preg_replace("/[\n\t]+/", " ", $sql);
CAST('_wpg' AS BINARY(255))
BINARY '_wpg'
我正在使用MediaWiki DatabaseMysql类来执行查询和获取行,但它是一个非常薄的抽象,我确定这不是问题(见下文)。
SELECT
prop.name AS prop_name, prop.count AS prop_count, prop.type AS prop_type,
val.value AS val_value, val.unit AS val_unit, val.count AS val_count
FROM
(
SELECT
s_id, name, type, COUNT(foo.name) AS count
FROM (
(
SELECT
cl.cl_to AS cat_name, s.smw_id AS s_id, s.smw_sortkey AS name, spec.value_string AS type
FROM `smw_ids` s
INNER JOIN (`categorylinks` cl, `page` p, `smw_ids` s2, `smw_atts2` a)
ON (cl.cl_from = p.page_id AND
p.page_title = s2.smw_title AND
s2.smw_id = a.s_id AND
a.p_id = s.smw_id)
LEFT JOIN `smw_spec2` spec ON s.smw_id = spec.s_id
)
UNION ALL
(
SELECT
cl.cl_to AS cat_name, s.smw_id AS s_id, s.smw_sortkey AS name, '_wpg' AS type
FROM `smw_ids` s
INNER JOIN (`categorylinks` cl, `page` p, `smw_ids` s2, `smw_rels2` a)
ON (cl.cl_from = p.page_id AND
p.page_title = s2.smw_title AND
s2.smw_id = a.s_id AND
a.p_id = s.smw_id)
)
) AS foo
WHERE foo.cat_name = 'Derp'
GROUP BY name
ORDER BY count DESC
LIMIT 10
) AS prop
INNER JOIN
(
SELECT
bar.p_id AS p_id, bar.value AS value, bar.unit AS unit, COUNT(bar.value) AS count,
IF( @prev != p_id, @rownum := 1, @rownum := @rownum+1 ) AS rank,
@prev := p_id
FROM (
(SELECT a.p_id AS p_id, a.value_xsd AS value, a.value_unit AS unit FROM `smw_atts2` a)
UNION ALL
(SELECT r.p_id AS p_id, s.smw_sortkey AS value, NULL AS unit
FROM `smw_rels2` r INNER JOIN `smw_ids` s ON r.o_id = s.smw_id)
) AS bar
GROUP BY value, unit
ORDER BY count DESC
) AS val
ON prop.s_id = val.p_id
WHERE val.rank <= 50
ORDER BY prop_count DESC, prop_name, val_count DESC, val_value
编辑:以下测试脚本不输出任何内容。 query.sql完全包含上面的查询,写入MediaWiki数据库类中mysql_query()调用之前的文件。
$db = mysql_connect('localhost', 'root', '');
mysql_select_db('mediawiki', $db);
$res = mysql_query(file_get_contents("query.sql"), $db);
while ($row = mysql_fetch_assoc($res)) {
var_dump($row);
}
echo mysql_error($db);
编辑:我导入了一个巨大的数据库转储,然后,当我加载PHP页面时,有一个明显的等待似乎表明查询正在运行,但仍然没有显示结果。我最终重新编写了查询,我不再有这个问题了。
答案 0 :(得分:0)
尝试此操作以更好地检测和报告错误:
$db = mysql_connect('localhost', 'root', '');
mysql_select_db('mediawiki', $db);
$res = mysql_query(file_get_contents("query.sql"), $db);
if (!$res) {
print "SQL Error ".mysql_errno().":".mysql_error().", from query: '".file_get_contents("query.sql")."'";
} else {
while ($row = mysql_fetch_assoc($res)) {
var_dump($row);
}
}
答案 1 :(得分:0)
在mysql_connect
:
mysql_query('SET NAMES utf8;');