Question

我有像这样的json数据，

var data = [ { _id: 5abb46b060808f3a2096f91d,
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: 5ab243ac73959deb3ad79fec,
    description: 'suffering from pain',
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5af143a779f06c22f5359be4,
    patient_name: 'Rajesh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: 5aaa628e9ae2a2a642b7495c,
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5af144685f2f292b2cc3af6d,
    patient_name: 'krishh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: 5aaa628e9ae2a2a642b7495c,
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5abb46b060808f3a2096f91d,
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: 5ab243ac73959deb3ad79fec,
    description: 'suffering from pain',
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 } ]

其中_id: 5abb46b060808f3a2096f91d重复两次，但我希望此数据对象包含unique _id，请帮我解决

更新

这是我的API从db获取此数据，我只是从同一个集合中获取数据两次，现在我想将最终的json设为唯一（_id）

function billing_read_all(req, res) {
    var auth_data = res.locals.result;
    var searchParam = { token: auth_data[0].token }
    model.find("doctor", searchParam, function (doctor_data) {
        var searchParam1 = { doctor_id: doctor_data[0]._id }
        model.find("patient", searchParam1, function (patient_data) {
            var searchParam2={charge_id:ObjectId("5ab243ac73959deb3ad79fec")}
            model.find("patient", searchParam2, function (patient_data2) {
                var data = patient_data.concat(patient_data2)
                console.log(_.uniq(data))
                res.send(_.uniq(data))
            // res.send(patient_data)
            })
        })
    })
}

Answer 1

您可以将Map对象用于此目的：

var data = [ { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af143a779f06c22f5359be4',
    patient_name: 'Rajesh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af144685f2f292b2cc3af6d',
    patient_name: 'krishh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' } ];


var patientMap = new Map();

data.forEach(row => {
    if (!patientMap.has(row._id.toString())) patientMap.set(row._id.toString(), row);
});

// One entry per unique ID now
for (var value of patientMap.values()) {
  console.log(value);
};

或枚举：

patientMap.forEach((row) => {
    console.log(row);
});

并将其变回数组：

let newArray = [...patientMap.values()]
console.log(newArray);

Answer 2

您可以array#reduce与Object.values()一起使用_id对数据进行分组。

var data = [ { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id:'5af143a779f06c22f5359be4', patient_name: 'Rajesh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af144685f2f292b2cc3af6d',patient_name: 'krishh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn',gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' } ],
    result = Object.values(data.reduce((r,o) => {
      r[o._id] = r[o._id] || {...o};
      return r;
    },{}));
console.log(result);

ES5代码

'use strict';

var _extends = Object.assign || function (target) { for (var i = 1; i < arguments.length; i++) { var source = arguments[i]; for (var key in source) { if (Object.prototype.hasOwnProperty.call(source, key)) { target[key] = source[key]; } } } return target; };

var data = [{ _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af143a779f06c22f5359be4', patient_name: 'Rajesh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af144685f2f292b2cc3af6d', patient_name: 'krishh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }],
    result = Object.values(data.reduce(function (r, o) {
  r[o._id] = r[o._id] || _extends({}, o);
  return r;
}, {}));
console.log(result);

Answer 3

如果您使用像underscore.js这样的库，它将成为一个单行解决方案，请参阅下面的代码段。你基本上告诉下划线返回一个只包含唯一项的新数组，唯一的标准是_id。

＆＃13;

var data = [ { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af143a779f06c22f5359be4',
    patient_name: 'Rajesh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af144685f2f292b2cc3af6d',
    patient_name: 'krishh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' } ];

var filteredData = _.uniq(data, (item) => item._id);
console.log(filteredData);

＆＃13;

<script src="http://underscorejs.org/underscore-min.js"></script>

＆＃13;

节点js中的唯一json数据对象

3 个答案: