Question

我有一个包含以下关系的数据库：

有projects - 人们可以购买的东西，也有user_id，

有backers - 购买的人，

有orders - 每个订单都是按Project购买Backer（Backer只能购买一次Project。这是一笔金额 - 显示Backer支付购买Project

的费用

我需要的是撰写以下查询 - 鉴于$user_id，$count和$sum找到至少投资$count个项目的所有支持者user_id等于$user_id，并且这些项目的购买金额高于$sum。

  Backer::whereHas('projects', function ($q) use ($sum, $userId){

        $q->where('user_id', $userId);

    }, '>=', $leastProjectCount)->get();

但它并不限制购买的$sum

更新所以我提出了这个问题：

select  * from `backers` \r\n
                    WHERE id > 0 \r\n
                    AND (select count(*)\r\n
                           FROM `projects` \r\n
                           inner join `orders` on `projects`.`id` = `orders`.`project_id` \r\n
                           where `backers`.`id` = `orders`.`backer_id` \r\n
                           and `user_id` = 6 \r\n
                           and exists (\r\n
                               select * \r\n
                               from `tags` \r\n
                               inner join `project_tag` on `tags`.`id` = `project_tag`.`tag_id` \r\n
                               where `projects`.`id` = `project_tag`.`project_id` \r\n
                               and `id` in (27)\r\n
                           ) \r\n
                          ) >= 1 \r\n
                    AND (select sum(orders.amount)\r\n
                           FROM `projects` \r\n
                           inner join `orders` on `projects`.`id` = `orders`.`project_id` \r\n
                           where `backers`.`id` = `orders`.`backer_id` \r\n
                           and `user_id` = 6 \r\n
                           and exists (\r\n
                               select * \r\n
                               from `tags` \r\n
                               inner join `project_tag` on `tags`.`id` = `project_tag`.`tag_id` \r\n
                               where `projects`.`id` = `project_tag`.`project_id` \r\n
                               and `id` in (27)\r\n
                           ) \r\n
                          ) >= 12

请注意，子查询几乎相同，只是第一个使用COunt(*)而第二个使用sum(orders.amount)。并且还要注意，如果设置了所有参数，则运行此查询，但是如果未设置某些参数，则可以更短。我得到的问题是我没有对这样的查询进行分页。

Answer 1

试试这个：

Backer::whereHas('projects', function ($q) use ($sum, $userId){
    $q->where('user_id', $userId)
        ->havingRaw('SUM(amount) > ? ', [$sum]);

}, '>=', $leastProjectCount)->get();

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