我花了几个小时才找到处理这个对象数组的方法：
[
{
"value": "foo01",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo02",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo03",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo04",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "val1",
"Diagnosis_Code": "foo03",
"name": "bar2"
},
{
"value": "val2",
"Diagnosis_Code": "foo01",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo04",
"name": "bar2"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo04",
"name": "bar3"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar3"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo02",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo04",
"name": "bar4"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar4"
}
]
我的预期JSON是这样的：
[
{
"name":"bar",
"value":[
{
"value": "foo01",
"Diagnosis_Code": ["Tidak ada"],
"name": "bar",
},
{
"value": "foo02",
"Diagnosis_Code": ["Tidak ada"],
"name": "bar",
},
{
"value": "foo03",
"Diagnosis_Code": ["Tidak ada"],
"name": "bar",
},
{
"value": "foo04",
"Diagnosis_Code": ["Tidak ada"],
"name": "bar",
}
]
},
{
"name": "bar2",
"value": [
{
"value": "val1",
"Diagnosis_Code": ["foo03"],
"name": "bar2",
},
{
"value": "val2",
"Diagnosis_Code": ["foo01"],
"name": "bar2",
},
{
"value": "val3",
"Diagnosis_Code": ["foo02", "foo04"],
"name": "bar2",
}
]
},
{
"name": "bar3",
"value":[
{
"value": "val1",
"Diagnosis_Code": ["foo01"],
"name": "bar3",
},
{
"value": "val2",
"Diagnosis_Code": ["foo03", "foo04"],
"name": "bar3",
},
{
"value": "val3",
"Diagnosis_Code": ["foo02"],
"name": "bar3",
},
]
},
{
"name": "bar4",
"value": [
{
"value": "val1",
"Diagnosis_Code": ["foo01", "foo02", "foo04"],
"name": "bar4",
},
{
"value": "val2",
"Diagnosis_Code": ["foo03"],
"name": "bar4",
},
]
},
]
我想将重复name值放入Object，如果json的Diagnosis_Code与另一个值相同，则将其放入数组
我现在使用的代码只是使用reduce来处理name，但我不知道如何处理Diagnosis_Code属性：
var orgArray = [{"value":"foo01","Diagnosis_Code":"Tidak ada","name":"bar"},{"value":"foo02","Diagnosis_Code":"Tidak ada","name":"bar"},{"value":"foo03","Diagnosis_Code":"Tidak ada","name":"bar"},{"value":"foo04","Diagnosis_Code":"Tidak ada","name":"bar"},{"value":"val1","Diagnosis_Code":"foo03","name":"bar2"},{"value":"val2","Diagnosis_Code":"foo01","name":"bar2"},{"value":"val3","Diagnosis_Code":"foo02","name":"bar2"},{"value":"val3","Diagnosis_Code":"foo04","name":"bar2"},{"value":"val1","Diagnosis_Code":"foo01","name":"bar3"},{"value":"val2","Diagnosis_Code":"foo03","name":"bar3"},{"value":"val2","Diagnosis_Code":"foo04","name":"bar3"},{"value":"val3","Diagnosis_Code":"foo02","name":"bar3"},{"value":"val1","Diagnosis_Code":"foo01","name":"bar4"},{"value":"val1","Diagnosis_Code":"foo02","name":"bar4"},{"value":"val1","Diagnosis_Code":"foo04","name":"bar4"},{"value":"val2","Diagnosis_Code":"foo03","name":"bar4"}];
var newArray = orgArray.reduce(function(acc, curr) {
var findIfNameExist = acc.findIndex(function(item) {
return item.name === curr.name;
})
if (findIfNameExist === -1) {
let obj = {
'name': curr.name,
"value": [curr]
}
acc.push(obj)
} else {
acc[findIfNameExist].value.push(curr)
}
return acc;
}, []);
console.log(newArray)
有没有办法处理将重复的Diagnosis_Code转换为数组？
答案 0 :(得分：2)
这是另一个例子！
首先，我使用reduce来减少你的对象，然后，我使用map来重新映射它以获得预期的格式;）
这可能不是最佳性能方式，但我发现它是更易于维护和可读的方式。
我希望这很明确，并会帮助你：D
const input = [
{
"value": "foo01",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo02",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo03",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo04",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "val1",
"Diagnosis_Code": "foo03",
"name": "bar2"
},
{
"value": "val2",
"Diagnosis_Code": "foo01",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo04",
"name": "bar2"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo04",
"name": "bar3"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar3"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo02",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo04",
"name": "bar4"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar4"
}
];
// Condensed/reduced object.
let output = input.reduce((accum, item) => {
if(!accum[item.name]) {
accum[item.name] = {};
}
if(!accum[item.name][item.value]) {
accum[item.name][item.value] = [];
}
accum[item.name][item.value].push(item.Diagnosis_Code);
accum[item.name][item.value].original = item;
return accum;
}, {});
// Object remapped to fit your expected format.
output = Object.keys(output).map((itemName) => {
return {
'name': itemName,
'value': Object.keys(output[itemName]).map((valueName) => {
const patchedOriginalItem = output[itemName][valueName].original;
patchedOriginalItem['Diagnosis_Code'] = output[itemName][valueName];
return patchedOriginalItem;
})
};
});
console.log(output);
答案 1 :(得分：1)
使用.reduce将数组转换为对象，然后您需要.find两次查看匹配的name然后匹配value对象存在。 find（或.findIndex）只是一次赢得不够。
const input = [
{
"value": "foo01",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo02",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo03",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "foo04",
"Diagnosis_Code": "Tidak ada",
"name": "bar"
},
{
"value": "val1",
"Diagnosis_Code": "foo03",
"name": "bar2"
},
{
"value": "val2",
"Diagnosis_Code": "foo01",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar2"
},
{
"value": "val3",
"Diagnosis_Code": "foo04",
"name": "bar2"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar3"
},
{
"value": "val2",
"Diagnosis_Code": "foo04",
"name": "bar3"
},
{
"value": "val3",
"Diagnosis_Code": "foo02",
"name": "bar3"
},
{
"value": "val1",
"Diagnosis_Code": "foo01",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo02",
"name": "bar4"
},
{
"value": "val1",
"Diagnosis_Code": "foo04",
"name": "bar4"
},
{
"value": "val2",
"Diagnosis_Code": "foo03",
"name": "bar4"
}
];
const output = input.reduce((accum, item) => {
const { name } = item;
let foundNameObj = accum.find(({ name: findName }) => findName === name);
if (!foundNameObj) {
foundNameObj = { name, value: [] };
accum.push(foundNameObj);
}
const foundValObj = foundNameObj.value.find(({ value }) => value === item.value);
if (!foundValObj) {
// value hasn't appeared before, we can just push the item:
foundNameObj.value.push({...item, Diagnosis_Code: [item.Diagnosis_Code] });
return accum;
}
foundValObj.Diagnosis_Code.push(item.Diagnosis_Code);
return accum;
}, [])
console.log(output);
不要混用var和let / const - 如果你正在使用ES6，你应该使用const，除了当您需要重新分配时，使用let。 （var被提升并且具有功能范围而不是阻止范围，这是不直观的并且可能导致意外错误）