Question

我的json结构就像，

{
"members": [
{
  "available": true,
  "firstName": "Jackie",
  "lastName": "Kane",
  "religion": "christianity"
},
{
  "available": true,
  "firstName": "Micke",
  "lastName": "Muhru",
  "religion": "Buddhism"
}
]
}

我使用以下代码从文件中读取

InputStream inputStream = getResources().openRawResource(R.raw.quote);

    ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

    int ctr;
    try {
        ctr = inputStream.read();
        while (ctr != -1) {
            byteArrayOutputStream.write(ctr);
            ctr = inputStream.read();
        }
        inputStream.close();
    } catch (IOException e) {
        e.printStackTrace();
    }

    JSONObject jObject = null;
    try {
        jObject = new JSONObject(
                byteArrayOutputStream.toString());
    } catch (JSONException e) {
        e.printStackTrace();
    }

    Gson g = new Gson();

    MemberList responseData = g.fromJson(jObject.toString(), MemberList .class);

现在我需要在成员Object中添加另一个属性memberId。新的Json文件看起来应该是，

{
"members": [
{
  "memberId": 1,
  "available": true,
  "firstName": "Jackie",
  "lastName": "Kane",
  "religion": "christianity"
},
{
  "memberId": 2,
  "available": true,
  "firstName": "Micke",
  "lastName": "Muhru",
  "religion": "Buddhism"
}
]
}

如何将其写入Raw文件夹中的文件？

Answer 1

将另一个变量 memberId 添加到您的类 MemberList 中，在解析JSON结果后，使用您的值填充memberId。

public class Member {

    @SerializedName("memberId")
    private int memberId;

    @SerializedName("available")
    private boolean available;

    @SerializedName("firstName")
    private String firstName;

    @SerializedName("lastName")
    private String lastName;

    @SerializedName("religion")
    private String religion;

    public void setMemberId(int memberId) {
        this.memberId = memberId;
    }
}

如何将新属性添加到json对象中并将其写入文件中？

1 个答案: