Question

我正在使用下面的代码。得到这个输出。

输出

标题：{"id" : 12345, "value" : "123", "person" : "1"}

CDD：{"CDDid" : 3456 }

但我需要的输出如下：

标题ID 12345

标题值123

标题人1

CDD CDDid 3456

import org.json.JSONException;
import org.json.JSONObject;

public class Test{

private static HashMap<String, Object> getHashMapFromJson(String json) throws JSONException {
    HashMap<String, Object> map = new HashMap<String, Object>();
    JSONObject jsonObject = new JSONObject(json);
    for (Iterator<String> it = jsonObject.keys(); it.hasNext();) {
        String key = it.next();
        map.put(key, jsonObject.get(key));
    }
    return map;
}
   public static void main(String[] args ){

   String json = " { \"Header\" : {\"id\" : 12345, \"value\" : \"123\", \"person\" : \"1\"} ,\"CDD\" : {\"CDDid\" : 3456 }}";
    try {
        HashMap<String, Object> map = getHashMapFromJson(json);
        for (String key : map.keySet()) {
            System.out.println(key + ": " + map.get(key));
        }
    } catch (JSONException e) {
        System.out.println("JsonTest" + "Failed parsing " + json + e);
    }
   }

   }

Answer 1

这是我的解决方案，我希望在getHashMapFromJson方法中已经正确使用。

toMap方法是简化版from this answer，如果你的json更复杂，你可能想要从该答案和toMap方法中实现完整的toList方法。

private static HashMap<String, Object> getHashMapFromJson(String json) throws JSONException {
    HashMap<String, Object> map = new HashMap<String, Object>();
    JSONObject jsonObject = new JSONObject(json);
    for (Iterator<String> it = jsonObject.keys(); it.hasNext();) {
        String key = it.next();

        JSONObject value = jsonObject.getJSONObject(key);
        Map<String, Object> valueMap = toMap((JSONObject) value);
        valueMap.forEach((k,v) -> map.put(key + " " + k, v));
    }
    return map;
}

public static Map<String, Object> toMap(JSONObject object) throws JSONException {
    Map<String, Object> map = new HashMap<String, Object>();

    Iterator<String> keysItr = object.keys();
    while(keysItr.hasNext()) {
        String key = keysItr.next();
        Object value = object.get(key);

        map.put(key, value);
    }
    return map;
}

Answer 2

String headerId = json.getJSONObject("Header").getString("id");

String headerValue = json.getJSONObject("Header").getString("value");

String headerperson = json.getJSONObject("Header").getString("person");

String CDDid = json.getJSONObject("CDD").getString("CDDid ");

这种方式可以检索json数据

以下格式的Json到csv

2 个答案: