Question

我已经为服装网站创建了一个登录表单。我已经使用了isset（）函数和按钮上的if语句单击说如果单击按钮...执行此操作....但是，当我在浏览器上运行时（我使用xammp作为我的本地主机），页面工作正常但是当我输入凭据并按下提交按钮时，它不会重定向到下一页，或者甚至没有回显“登录成功”或“登录失败。我在php中使用了错误报告功能来跟踪错误但它没有显示任何错误无论是。这是我的代码

IndexLogin.html

    <html lang="en">
    <head>
    <title>Login </title>
    </head>
    <body>

     <div class="limiter">
      <div class="container-login100">
        <div class="wrap-login100">
            <form class="login100-form validate-form">
                <form method="POST" form action="login.php">
                <span class="login100-form-title p-b-34">
                    SHAARANYA~<br>
                    Account Login
                </span>

                <div class="wrap-input100 rs1-wrap-input100 validate-input 
                m-b-20" data-validate="Type email">
                    <input id="email" class="input100" type="text" 
                     name="email" placeholder="email" >
                    <span class="focus-input100"></span>
                </div>
                <div class="wrap-input100 rs2-wrap-input100 validate-input 
                 m-b-20" data-validate="Type password">
                    <input class="input100" type="password" name="pass" 
                     placeholder="Password" >
                    <span class="focus-input100"></span>
                </div>

                <div class="container-login100-form-btn">
                    <button class="login100-form-btn"
                      button type="submit" name="submit">
                        Sign in
                    </button>
                </div>

                <div class="w-full text-center p-t-27 p-b-239">
                    <span class="txt1">
                        Forgot
                    </span>

                    <a href="#" class="txt2">
                        User name / password?
                    </a>
                    <br>
                    <br>
                    <p><font size="3">Not a Member Yet? Join us for FREE!
                    <br><br><a href="#"><b> SIGN UP </font></b> </a></p>

                </div>


            </form>
             </body>
             </html>

的login.php

      <?php

     error_reporting(E_ALL);
     ini_set('display_errors', '1');

     $servername = "localhost";
     $username = root;
      $password = "";
      $dbname="company";

       $conn = new mysqli($servername,$username,$password,$dbname);

       // Check connection
       if ($conn->connect_error) {
       die("Connection failed: " . $conn->connect_error);
       } 


       if(isset($_POST['submit'])){

       $email=$_POST['email'];
       $pass=$_POST['pass'];

       $sql = "SELECT * FROM login WHERE email = '".$email."' and pass = 
       '".$pass."'";

       $result = mysqli_query( $conn,$sql);
        if(mysql_num_rows($result)==1){
         echo "Login Successful";
       }

      else {
      echo "Failed To Login";
       }
        }       
      ?>

Answer 1

我已经清理了你的HTML脚本。请现在试试，希望这对你有用。

<html lang="en">
      <head>
        <title>Login</title>
      </head>
    <body>
       <div class="limiter">
          <div class="container-login100">
            <div class="wrap-login100">           
                    <form method="POST" form action="login.php">
                    <span class="login100-form-title p-b-34">
                        SHAARANYA~<br>
                        Account Login
                    </span>

                    <div class="wrap-input100 rs1-wrap-input100 validate-input 
                    m-b-20" data-validate="Type email">
                        <input id="email" class="input100" type="text" 
                         name="email" placeholder="email" >
                        <span class="focus-input100"></span>
                    </div>
                    <div class="wrap-input100 rs2-wrap-input100 validate-input 
                     m-b-20" data-validate="Type password">
                        <input class="input100" type="password" name="pass" 
                         placeholder="Password" >
                        <span class="focus-input100"></span>
                    </div>

                <div class="container-login100-form-btn">
                  <button class="login100-form-btn" type="submit" name="submit">
                            Sign in
                        </button>
                    </div>

                    <div class="w-full text-center p-t-27 p-b-239">
                        <span class="txt1">
                            Forgot
                        </span>

                        <a href="#" class="txt2">
                            User name / password?
                        </a>
                        <br>
                        <br>
                        <p><font size="3">Not a Member Yet? Join us for FREE!
                        <br><br><a href="#"><b> SIGN UP </font></b> </a></p>

                    </div>
                </form>
                 </body>
                 </html>

php中的isset（）函数无法正常工作，但也没有显示错误

1 个答案: