熊猫，用字符串打印变量

Question

我有一个看起来像这样的数据框（新）：

num  name1  name2
11    A      AB
14    Y      YX
25    L      LS
39    Z      ZT
....

我只是想在print语句中提取num值，这样我的输出看起来像这样：

The value is 11
The value is 14
The value is 25
...

我不确定这样做的正确格式是什么，因为下面的代码只是迭代“值是”。

 for index, row in new.iterrows():
     print('The value is').format(new['num'])

Answer 1

使用str.join和f-strings

print('\n'.join(f'The value is {n}' for n in new.num))

The value is 11
The value is 14
The value is 25
The value is 39

略有变化，以及更多显示如何使用print功能...

print(*(f'The value is {n}' for n in new.num), sep='\n')

The value is 11
The value is 14
The value is 25
The value is 39

Answer 2

略微更改您的代码

for index, row in df.iterrows():
    print('The value is {0}'.format(row['num']))

The value is 11
The value is 14
The value is 25
The value is 39

Answer 3

您可以直接遍历Series对象（与DataFrame对象不同）。这允许你这样做：

for num in new['num']:
    print('The value is ' + str(num))

Answer 4

您还可以尝试以下操作：

for val in new.num: print('This is ', val)

结果：

This is  11
This is  14
This is  25
This is  39