当我尝试将用户注册到我的sql数据库并且没有在logcat中抛出有用的错误提示时,我得到一个空的Toast作为响应。
请问这可能是什么原因? registerProcess
private void registerProcess(final String name, final String email, final String password) {
// Tag used to cancel the request
String tag_string_req = "req_register";
pDialog.setMessage("Registering ...");
showDialog();
StringRequest strReq = new StringRequest(Request.Method.POST,
Functions.REGISTER_URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "Register Response: " + response);
hideDialog();
try {
JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");
if (!error) {
Functions logout = new Functions();
logout.logoutUser(getApplicationContext());
Bundle b = new Bundle();
b.putString("email", email);
Intent i = new Intent(RegisterActivity.this, EmailVerify.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
i.putExtras(b);
startActivity(i);
pDialog.dismiss();
finish();
} else {
// Error occurred in registration. Get the error
// message
String errorMsg = jObj.getString("message");
Toast.makeText(getApplicationContext(),errorMsg, Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Registration Error: " + error.getMessage());
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
hideDialog();
}
}) {
@Override
protected Map<String, String> getParams() {
// Posting params to register url
Map<String, String> params = new HashMap<String, String>();
params.put("name", name);
params.put("email", email);
params.put("password", password);
return params;
}
};
// Adding request to request queue
MyApplication.getInstance().addToRequestQueue(strReq, tag_string_req);
}
private void showDialog() {
if (!pDialog.isShowing())
pDialog.show();
}
private void hideDialog() {
if (pDialog.isShowing())
pDialog.dismiss();
}
}
网络服务
/**
* Adding new user to mysql database
* returns user details
*/
public function storeUser($fname, $lname, $email, $uname, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$result = mysql_query("INSERT INTO users(unique_id, firstname, lastname, email, username, encrypted_password, salt, created_at) VALUES('$uuid', '$fname', '$lname', '$email', '$uname', '$encrypted_password', '$salt', NOW())");
// check for successful store
if ($result) {
// get user details
$uid = mysql_insert_id(); // last inserted id
$result = mysql_query("SELECT * FROM users WHERE uid = $uid");
// return user details
return mysql_fetch_array($result);
} else {
return false;
}
}
答案 0 :(得分:0)
据我所见,代码似乎没有错误。 您应该检查 curl 得到的答案,然后查看返回的内容。
答案 1 :(得分:0)
从您的Web服务获取响应,因为您正在执行Volley的POST请求,因此您不需要JSON。你的吐司是空的,因为你只是在解释错误的反应,而像String errorMsg = jObj.getString("message");
这样的对象将是空的。
要获得响应,您应该这样做:
if (response.equalsIgnoreCase("yourResponseFromTheWebService")) {
...
Toast
} else if (response.equalsIgnoreCase("OtherPossibleResponse")){
....
Toast
} else{
....
Toast
}
编辑:
我设法在您的网络服务代码中发现了两件事。
1-当您刚从应用程序发送信息时,为什么要尝试从同一用户的服务器获取信息?这没有意义。您应该像使用电子邮件一样附加您的意图数据。
2- Volley期望一个String类型的响应,你同时给他不同的格式。
所以这是您的代码的修改版本:
网络服务:
public function storeUser($fname, $lname, $email, $uname, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$result = mysql_query("INSERT INTO users(unique_id, firstname, lastname, email, username, encrypted_password, salt, created_at) VALUES('$uuid', '$fname', '$lname', '$email', '$uname', '$encrypted_password', '$salt', NOW())");
// check for successful store
if ($result) {
echo "successful";
} else {
echo "notsuccessful";
}
}
<强>的Android 强>
private void registerProcess(final String name, final String email, final String password) {
// Tag used to cancel the request
String tag_string_req = "req_register";
pDialog.setMessage("Registering ...");
showDialog();
StringRequest strReq = new StringRequest(Request.Method.POST,
Functions.REGISTER_URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "Register Response: " + response);
hideDialog();
if (response.equalsIgnoreCase("successful")) {
Functions logout = new Functions();
logout.logoutUser(getApplicationContext());
Bundle b = new Bundle();
//add other informations you need like name ect..
b.putString("email", email);
Intent i = new Intent(RegisterActivity.this, EmailVerify.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
i.putExtras(b);
startActivity(i);
pDialog.dismiss();
finish();
} else if(response.equalsIgnoreCase("notsuccessful")) {
Toast.makeText(getApplicationContext(),"new user wasn't registered successfully", Toast.LENGTH_LONG).show();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Registration Error: " + error.getMessage());
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
hideDialog();
}
}) {
@Override
protected Map<String, String> getParams() {
// Posting params to register url
Map<String, String> params = new HashMap<String, String>();
params.put("name", name);
params.put("email", email);
params.put("password", password);
return params;
}
};
// Adding request to request queue
MyApplication.getInstance().addToRequestQueue(strReq, tag_string_req);
}
private void showDialog() {
if (!pDialog.isShowing())
pDialog.show();
}
private void hideDialog() {
if (pDialog.isShowing())
pDialog.dismiss();
}
}
注意:
如果你想知道你的Mysql请求中的错误没有在你的应用程序上显示,请在浏览器中查看。
我希望这对你有用