如何在oracle中组合两列

Question

我有一个查询

select
    city,
    month,
    month_number,
    sum(totalcount) as totalcount,
    sum(total_value) total_value
from
(
    select
        city,
        to_char( testdate, 'Mon') month,
        to_number( to_char( testdate, 'mm' ) ) month_number,
        count( totalcount ) totalcount,
        sum( total_value ) total_value
    from 
        testtable
    group by
        city,
        testdate
)
group by
    city,
    month,
    month_number
order by
    1,3

将结果显示为图像1，如何修改此查询可以将结果显示为图像2？

Answer 1

在group by中使用Oracle ROLLUP函数来实现所需的结果。

select
city,
month,
month_number,
sum(totalcount) as totalcount,
sum(total_value) total_value
from
(
    select
        city,
        to_char( testdate, 'Mon') month,
        to_number( to_char( testdate, 'mm' ) ) month_number,
        count( totalcount ) totalcount,
        sum( total_value ) total_value
    from 
        testtable
    group by
        city,
        testdate
)
group by
    city,
    ROLLUP (month,month_number)
order by
    1,3

Answer 2

尝试以下SQL。

SELECT city, month,month_number
    sum(totalcount) as totalcount,
    sum(total_value) total_value
FROM   ( select
        city,
        to_char( testdate, 'Mon') month,
        to_number( to_char( testdate, 'mm' ) ) month_number,
        count( totalcount ) totalcount,
        sum( total_value ) total_value
    from 
        testtable
    group by
        city,
        testdate) x
GROUP BY ROLLUP (city, month,month_number)
ORDER BY 1,3