Question

我有以下型号：

class Clean(models.Model):
    name = models.CharField(max_length=100)
    cv = models.TextField(max_length=10000)
    cvfile = models.FileField()

当用户从表单提交名称和文件时，我正在尝试将cvfile的内容写入cv。我确定这可以完成，因为文件和文本字段将在同一个对象中。该文件将始终为.txt，因此我假设可以执行简单的.read（）。

我应该有一个表单调用的函数来执行此操作吗？如果是这样，怎么办呢？

def writeCV(self):
        get_text = cvfile.open().read()
        #write to cv field somehow

        return self.cv

我正在使用django 1.9

来自Messaoud的回复

Environment:


Request Method: POST
Request URL: http://127.0.0.1:8000/cleaner/clean/add/

Django Version: 1.9
Python Version: 3.6.4
Installed Applications:
['cleaner.apps.CleanerConfig',
 'django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback:

File "C:\Python\Python36-32\lib\site-packages\django\core\handlers\base.py" in get_response
  149.                     response = self.process_exception_by_middleware(e, request)

File "C:\Python\Python36-32\lib\site-packages\django\core\handlers\base.py" in get_response
  147.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "C:\Python\Python36-32\lib\site-packages\django\views\generic\base.py" in view
  68.             return self.dispatch(request, *args, **kwargs)

File "C:\Python\Python36-32\lib\site-packages\django\views\generic\base.py" in dispatch
  88.         return handler(request, *args, **kwargs)

File "C:\Python\Python36-32\lib\site-packages\django\views\generic\edit.py" in post
  255.         return super(BaseCreateView, self).post(request, *args, **kwargs)

File "C:\Python\Python36-32\lib\site-packages\django\views\generic\edit.py" in post
  221.             return self.form_valid(form)

File "C:\Python\Python36-32\lib\site-packages\django\views\generic\edit.py" in form_valid
  200.         self.object = form.save()

File "C:\Python\Python36-32\lib\site-packages\django\forms\models.py" in save
  451.             self.instance.save()

File "C:\Users\barry\Desktop\College\Year 4\Semester 2\cvCleaner\cvcleaner\cleaner\models.py" in save
  11.         get_text = self.cvfile.open().read()

Exception Type: AttributeError at /cleaner/clean/add/
Exception Value: 'NoneType' object has no attribute 'read'

Answer 1

您可以通过覆盖save

中的Model方法来执行此操作

class Clean(models.Model):
    name = models.CharField(max_length=100)
    cv = models.TextField(max_length=10000, blank = True, null = True)
    cvfile = models.FileField()

    def save(self, *args, **kwargs):
        get_text = self.cvfile.open().read()
        self.cv = get_text
        super(Clean, self).save(*args, **kwargs) # Call the "real" save() method.

或使用post_save信号

def writeCV(sender, instance, **kwargs):
    get_text = instance.cvfile.open().read()
    instance.cv = get_text
    instance.save()
post_save.connect(writeCV, sender=Clean)

Django：将文本从上传文件写入文本字段

1 个答案: