Question

我有一个包含以下内容的文件：

name: James
player: 2

name: Martin
player: 3
.
.

在＆＃39;之后有一个空格：＆＃39;名字和玩家后面跟另一个名字和玩家的换行符。

我试图访问詹姆斯和2，马丁和3没有＆＃39;名称＆＃39;和＆＃39;球员＆＃39;。我计划使用我试过的计数器：

filename = open("testing.txt","r", encoding = "utf-8")
playerFile = filename
lst = []
for line in playerFile:
    line = line.replace('\n','')  #replace newlines with an empty space
    lst.append(line)    #append into a lst for now

counter = 1    #initialize a counter
for i in range(len(lst)):
    if counter == 1:     #for name since name is on first line, hence take the string James
        ...              #how do i get just the string 'James'?
        counter +=1      #increment to go to line 2 which is the player
    elif counter == 2:    #for player
        ...
        counter +=1      #increment to go to line 3 which is a newline
    elif counter == 3:   #newline, empty, set back to 1
        counter = 1    #set back to one since the third line is empty

我们可以假设该文件的格式始终为＆＃39; name＆＃39;，然后是＆＃39; player＆＃39;然后是一条新线＆＃39;然后是另一个名字＆＃39;等等。

Answer 1

简单就是更好，为什么不迭代这些行并检查它是name还是player所以会相应地采取行动，例如（草稿）

for line in playerFile:
  attr = line.split()
  if atrr[0] == 'name:':
    # store name attr[1]
  elif attr[0] == 'player:':
    # store player attr[1]

注意：您需要处理空白行和包含其他文本的行以及输入文件中的所有方案......

Answer 2

playerFile = open("testing.txt","r", encoding = "utf-8")
lst = []
for line in playerFile:
  if line!='':
    lst.append(line)    #append into a lst for now

for sen in lst:
  words=sen.split()
  if words[0]=='name:':
    name=words[1]
  else:
    number=words[1]

用counter方法读取文件？

2 个答案: