Question

有谁知道为什么var2.set(E2.get())函数没有类型而不是int？

var1 = Tkinter.IntVar()
E1 = Tkinter.Entry(root, textvariable = var1  ,bd =5)
E1.pack(side = Tkinter.LEFT)
n =  var1.set(E1.get())

我收到了这个错误：

文件＆＃34; /home/rostom/Desktop/statistic.py"，第36行，在estimate_prob中对于范围内的m（0，m）： TypeError：range（）期望整数结束参数，得到NoneType。

整个代码

import numpy as np
import Tkinter
import tkMessageBox
root = Tkinter.Tk()
var1 = Tkinter.IntVar()
var2 = Tkinter.IntVar()
var3 = Tkinter.IntVar()
var4 = Tkinter.IntVar()
text1= Tkinter.StringVar()
text2= Tkinter.StringVar()
text3= Tkinter.StringVar()
text4= Tkinter.StringVar()

def seq_sum(n):
    x1 = 0
    x2 = 0

    for i in range(0,n):

        r = np.random.rand()
        if r > 0.5:
            x1=x1+1
        else:
            x2=x2+1
    return x1

def estimate_prob(n,k1,k2,m):
    ran=0
    for m in range(0,m):
        head = seq_sum(n)


        if k1<=head < k2:

           ran =ran  + 1

    p = ran/float(m)
    print ran

    return tkMessageBox.showinfo("results ", p)


L1 = Tkinter.Label(root, textvariable = text1)
L1.grid(row=0,column=0)
E1 = Tkinter.Entry(root, textvariable = var1  ,bd =5)
E1.grid(row=0,column=1)

text1.set("number of flips ")

n =  var1.set(E1.get())

L2 = Tkinter.Label(root, textvariable = text2)
L2.grid(row=1,column=0)
E2 = Tkinter.Entry(root, textvariable = var2  ,bd =5)
E2.grid(row=1,column=1)

text2.set("lower limit ")

k1 = var2.set(E2.get())

L3 = Tkinter.Label(root, textvariable = text3)
L3.grid(row=2,column=0)
E3 = Tkinter.Entry(root, textvariable = var3  ,bd =5)
E3.grid(row=2,column=2)

text3.set("upper limit ")

k2= var3.set(E3.get())

L4 = Tkinter.Label(root, textvariable = text4)
L4.grid(row=3,column=0)
E4 = Tkinter.Entry(root, textvariable = var4  ,bd =5)
E4.grid(row=3,column=1)

text4.set("number of trials ")

m = var4.set(E4.get())

B1 = Tkinter.Button(root,text = "calculate the probability", command = lambda:  estimate_prob(n,k1,k2,m) )
B1.grid(row=4,column=1)  
root.mainloop()

Answer 1

这句话看起来很奇怪：

ade, 12.3

为什么不把它写成

m = var4.set(E4.get())

因为m = var4.get()是分配给var4的IntVar？当您设置 IntVar时，操作将返回E4。

None

这适用于所有四个IntVars。

tkinter获取int值而不是nonetype

1 个答案: