gulp管不工作

Question

const gulp = require ('gulp');
const browserSync = require ('browser-sync').create();
const sass = require('gulp-sass');

//Compile Sass and inject into browser
gulp.task('sass', function(){
  return gulp.src(['node_modules/bootstrap/scss/bootstrap.scss','src/scss/*.scss']);
  .pipe(sass())
  .pipe(gulp.dest("src/css"))
  .pipe(browserSync.stream())
  });

.pipe正在抛出错误，我似乎无法让它发挥作用。这是它抛出的错误的快照

Answer 1

此行末尾有分号：

return gulp.src(['node_modules/bootstrap/scss/bootstrap.scss', 'src/scss/*.scss']);
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您应将其删除，以便在Stream返回的gulp.src上致电.pipe：

return gulp.src(['node_modules/bootstrap/scss/bootstrap.scss', 'src/scss/*.scss'])
    .pipe(sass())
    .pipe(gulp.dest("src/css"))
    .pipe(browserSync.stream())