Question

我想并行运行一些脚本，如果一切成功，我会执行一些额外的命令。但是，如果任何子shell失败，我想立即退出。

我想通过一个例子来解释更容易：

exit_in_1() {
  sleep 1
  echo "This should be the last thing printed"
  exit 1
}

exit_in_2() {
  sleep 2
  echo "This should not be printed"
  exit 1
}

exit_in_1 &
exit_in_2 &

echo "This should be printed immediately"

sleep 3

echo "This should not be printed also"

以上脚本打印所有回声。

Answer 1

感谢@ Mansuro的评论，我解决了我的问题：

exit_later() {
  sleep $1
  echo "This should be printed twice"
  exit $(($1-1))
}

pids=""
for i in {1..10}; do
  exit_later $i &
  pids+=" $!"
done

echo "This should be printed immediately"

for p in $pids; do
  if ! wait $p; then
    kill $pids
    exit 1
  fi
done

echo "This should not be printed"

如果任何子shell失败，Bash将完全失败

1 个答案: