我有这本词典:
appointment = { soccer = {
day : 20,
month : april
}
}
如何在同一结构中插入此dictio?
appointment = { gym = {
day : 5,
month : may
}
}
预期产出:
appointment = { soccer = {
day : 20,
month : april
},
gym = {
day : 5,
month : may
}
}
如何通过代码连接此dictio?
答案 0 :(得分:1)
如果您使用的是python 3.5或更高版本,则可以使用以下语法合并字典:
public async Task<ActionResult> RegisterPatient(RegisterViewModel model)
{
MYDb db = new MYDb();
Patient pt = new Patient();
pt.BirthDate = model.BirthDate;
pt.City = model.City;
pt.Country = model.Country;
pt.ProfilePicture = model.ProfilePicture;
pt.FName = model.FName;
int Pat_id = model.PatientID;
if (ModelState.IsValid)
{
ApplicationUser myuser = new ApplicationUser();
model.CreatedOn = DateTime.Now;
model.IsActive = true;
myuser.PatientID = Pat_id;
if (ModelState.IsValid)
{
var user = model.GetUser();
db.Patients.Add(pt);
db.SaveChanges();
var result = await UserManager.CreateAsync(user, model.Password);
if (result.Succeeded)
{
var idManager = new IdentityManager();
idManager.AddUserToRole(user.Id, model.User_type);
//await db.SaveChangesAsync();
await SignInAsync(user, isPersistent: false);
return RedirectToAction("Index", "Home");
}
else
{
AddErrors(result);
}
}
return RedirectToAction("Index", "Home");
}
// If we got this far, something failed, redisplay form
return View();
}
答案 1 :(得分:0)
如果dicts已存在,您可以查看dict.update()
。
简短的回答是:
>>> appointment = { 'soccer' : { 'day': 20, 'month': 'april' } }
>>> appointment2 = { 'gym' : { 'day': 5, 'month': 'may' } }
>>> appointment.update(appointment2)
>>> appointment
{'gym': {'day': 5, 'month': 'may'}, 'soccer': {'day': 20, 'month': 'april'}}
但是如果你正在制作这些词汇,那么以通常的方式添加新词条会更有意义(参见:Add new keys to a dictionary?):
>>> appointment = { 'soccer' : { 'day': 20, 'month': 'april' } }
>>> appointment['gym'] = {'day': 5, 'month': 'may'}
>>> appointment
{'gym': {'day': 5, 'month': 'may'}, 'soccer': {'day': 20, 'month': 'april'}}
答案 2 :(得分:0)
我认为您正在寻找appointment = { 'soccer' : { 'day' : 20, 'month' :'april' }}
appointment2 = {'gym': {'day': 20, 'month': 'april'}}
# update appointment with appointment2 values
appointment.update(appointment2)
{'soccer': {'day': 20, 'month': 'april'}, 'gym': {'day': 20, 'month': 'april'}}
方法
D.update([E,] ** F) - &gt;无。
从dict / iterable E和F。
更新D.如果E存在且具有.keys()方法,那么:对于E中的k:D [k] = E [k]
如果E存在且缺少.keys()方法,那么:对于k,v在E中:D [k] = v
在任何一种情况下,接着是:对于F中的k:D [k] = F [k]
你的情况,
appointment2
当appointment
变量更新到位时,// test.js
it('delete user', async () => {
const userByEmail = await request(app)
.get('/users/get-by-email/user@test')
.set('Accept', 'application/json')
.set('Authorization', config.get('test.tokens.admin'));
const result = await testIt('delete', `/users/${userByEmail.body._id}`);
expect(result).toEqual([401, 403, 401, 200]);
});
变量保持不变。