Question

我将一个从flask函数传递给另一个函数的列表，并且得到了这个值错误。

发送结束时的代码：

@app.route('/process', methods=['POST'])
def process():
    name = request.form['name']
    comment = request.form['comment']
    wickets = request.form['wickets']
    ga = request.form['ga']
    ppballs = request.form['ppballs']
    overs = request.form['overs']

    score = [name,comment,wickets,ga,ppballs,overs]
    results = []
    results = eval_score(score)
    print results

接收方结束：

def ml_model(data):
    col = pd.DataFrame(data,columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])
    predicted = predictor(col)

错误跟踪：

 ...
 line 1598, in dispatch_request
 return self.view_functions[rule.endpoint](**req.view_args)

 File "/Users/sbk/guestbook/guestbook.py", line 26, in process
 results = eval_score(score)

 File "/Users/sbk/guestbook/eval_score.py", line 6, in eval_score
 col = pd.DataFrame(data,columns=['runs','balls', 'wickets',  'ground_average', 'pp_balls_left', 'total_overs'])

 File "/Users/sbk/anaconda2/lib/python2.7/site-  packages/pandas/core/frame.py", line 385, in __init__
 copy=copy)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/frame.py", line 533, in _init_ndarray
 return create_block_manager_from_blocks([values], [columns, index])

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4631, in  create_block_manager_from_blocks
 construction_error(tot_items, blocks[0].shape[1:], axes, e)

 File "/Users/sbk/anaconda2/lib/python2.7/site-packages/pandas/core/internals.py", line 4608, in construction_error
 Open an interactive python shell in this framepassed, implied))

请让我知道我哪里出错。

Answer 1

只需更改

col = pd.DataFrame(data, columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

的

col = pd.DataFrame([data], columns=['runs','balls', 'wickets', 'ground_average', 'pp_balls_left', 'total_overs'])

您希望[data] pandas了解它们是行。

简单说明：

a = [1, 2, 3]
>>> pd.DataFrame(a)
   0
0  1
1  2
2  3

>>> pd.DataFrame([a])
   0  1  2
0  1  2  3

Answer 2

在使用回归系数（regressor.coeff_）制作数据帧时，我遇到了类似的问题，方括号给出了另一个错误，要求进行二维输入。如果出现此错误，请尝试在输入数组后附加[0]，以便将值拉出。例如：数据[0]

Answer 3

我遇到了类似的错误消息

传递值的形状为（68，1783），索引在数据框中暗示（68，68）

据我的猜测，我输入了数据ndarray的转置，就解决了问题

更改自

Features_Dataframe = pd.DataFrame(data=Features, columns=Feature_Labels)  # here Features ndarray is 68*1783

收件人

Features_Dataframe = pd.DataFrame(data=Features.transpose(), columns=Feature_Labels)  # Now Features array became 1783*68 i.e., 1783 rows and 68 columns

ValueError：传递值的形状是（1,6），索引暗示（6,6）

3 个答案: