Question

我正在尝试在给定范围内找到 Palindrome 数字。这是我的代码：

methods: {
  getSelectedItem: function(selected) {
    console.log(selected);
  },
  exportXML: function(selected) {
    console.log(selected);
    this.$http.get(
      'http://localhost:8080/api/exports/' + selected,
    });
  }
}

当我运行代码时，它只为第一个整数提供正确的输出。它不适用于给定范围内的其他整数。对此问题的任何建议/解决方案？为什么它不工作？

示例输出：

开始时间：33结束：55 33 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 [33]

Answer 1

你的temp在循环中没有递增1。

// temp is initialized to start at first
while(temp != 0){
    rem = temp % 10;
    rev = rev * 10 + rem;
    temp = temp / 10;
}
// at the end of this temp's value is entirely changed.
// above temp is incremented here, ideally temp at the start should be incremented. You can do this by initializing temp as i
temp++;

Answer 2

请试试这个

import java.util.Scanner;
import java.util.ArrayList;

public class PalindromeNums{
    public static void main(String [] args){
        Scanner input = new Scanner(System.in);
        int start,end,rem,rev=0,temp;
        ArrayList <Integer> palindrome = new ArrayList<>();
        System.out.print("Start : ");
        start = input.nextInt();
        System.out.print("End : ");
        end = input.nextInt();

     // Picking Each Number Of That Range;
        for(int i = start; i <= end; i++){
            temp =i;
            // Checking whether Its Palindrome Or Not
            while(temp != 0){
                rem = temp % 10;
                rev = rev * 10 + rem;
                temp = temp / 10;
            }

            System.out.println(rev);
            if(i == rev){
                palindrome.add(i);
            }
            rev = 0;
        }
        System.out.println(palindrome);

    }
}

Answer 3

当循环结束时，temp将为0，因此您不应该temp++。

相反，您需要将当前正在处理的号码指定为temp作为循环的第一行

temp = i;

Java程序，用于查找给定范围内的回文数

3 个答案: