Question

我不是DBA，我继承了此查询，但我不确定为什么我会收到sql_mode=only_full_group_by错误。特别是因为错误是在谈论result.fullURL而我在查询中没有看到。有人可以向我解释一下吗？

查询

SELECT *
FROM (
    SELECT content.*, content.navigationOrder AS sortOrder
    FROM LB_Content AS content
    INNER JOIN LB_Content AS other ON content.contentSectionId = other.contentSectionId
    WHERE other.fullURL = '/index'
    AND content.contentSlug <> 'index'
    GROUP BY content.contentId
    UNION
    SELECT content.*, query.sectionOrder AS sortOrder
    FROM LB_Content AS content, (
        SELECT section.*
        FROM LB_ContentSections AS section
        INNER JOIN LB_Content AS other ON section.parentContentSectionId = other.contentSectionId
        WHERE other.fullURL = '/index'
    ) AS query
    WHERE content.contentSectionId = query.contentSectionId
    AND content.contentSlug = 'index'
) as result,
LB_ContentTypes AS types
WHERE result.showInNavigation = 1
AND result.status = 1
AND result.published = 1
AND result.contentTypeId = types.contentTypeId
AND types.useOption = 1
GROUP BY result.contentId
ORDER BY result.sortOrder ASC

错误输出

SQLSTATE [42000]：语法错误或访问冲突：1055表达式＃2 SELECT列表不在GROUP BY子句中并包含nonaggregated 专栏＆＃39; result.fullURL＆＃39;这在功能上不依赖于列在GROUP BY子句中;这是不相容的的sql_mode = only_full_group_by

感谢您的帮助！

Answer 1

＆＃34;只有＆＃34;表示您的聚合查询必须在结果中的所有非聚合字段上进行分组。它们是否被隐藏＆＃34;无关紧要。在*中，必须将这些字段分组。

此查询甚至不应该开始分组;没有使用聚合函数。如果＆＃34;只有＆＃34;不是当前的设置，这个查询将是＆＃34;给我一个有效的随机结果，传递where条件，为每个contentId＆＃34;。

MySQL only_full_group_by错误

1 个答案: