Question

我只想计算最大值并在用户输入时输出。我被困住了，任何帮助都会受到赞赏。

df['subset_max'] = ''
for idx in abnormal_idx:
    idx_max = df[idx-5:idx+6].X.idxmax() 
    #note the +6 instead of +5 as the upbound is not consider, sorry for that
    if idx == idx_max:
        df.loc[idx,'subset_max'] = 'max of the subset'
    else:
        df.loc[idx, 'subset_max'] = 'subset max at %s' % idx_max

Answer 1

如评论中所述，您忘了添加花括号。试试这个...

BufferedReader input = new BufferedReader(new InputStreamReader(System.in));


int totalnum, number, num1, max, min;

System.out.println("How many integers are you entering?");
totalnum = Integer.parseInt(input.readLine());

System.out.println("Enter an integer");
number = Integer.parseInt(input.readLine());
max = number;
for (int ctr = 2; ctr <= totalnum; ctr++)
{
    number = Integer.parseInt(input.readLine());
    if (number > max){
        max = number;
    }
}
System.out.println("The max is "+ max);

Answer 2

IMO，没有必要使用ec2:Describe*来进行此类输入。我更喜欢使用void __fastcall Tdata::bcServerExecute(TIdContext *AContext) { String json = AContext->Connection->Socket->ReadLn(); TJSONObject* jo = (TJSONObject*)TJSONObject::ParseJSONValue(json); if (jo != 0) { TJSONPair* jp = (TJSONPair*)jo->Get("text"); String text = jp->JsonValue->Value(); jp = (TJSONPair*)jo->Get("font_size"); int font_size = _wtoi(jp->JsonValue->Value().c_str()); int tw = 0; double text_width = 0.0; //================================ TCanvas* canvas = new TCanvas(); if (canvas) { canvas->Handle = GetDC(0); canvas->Font->Size = font_size; tw = canvas->TextWidth(text); double ppi = Screen->PixelsPerInch; text_width = double(tw) / ppi; ReleaseDC(0,canvas->Handle); delete canvas; } String buf = String(text_width); //================================== AContext->Connection->IOHandler->WriteLn(buf); } }。

无论如何，只是为了提供一个替代答案，你可以阅读List和Collections，或许给你的同事/同学/讲师等留下深刻印象。

例如：

BufferedReader

* _{为了简单起见，我只是默认为5}

找到循环的最大数量

2 个答案: