在C#console应用程序

时间:2018-05-04 13:54:27

标签: c# google-drive-api console-application

我正在努力连接到谷歌驱动器,列出任何格式的每个文件,然后在我的硬盘上物理下载。我使用了谷歌API为我准备的方法。但我认为我工作的方式我只能访问每个文件的内容,所以我不能这样做。

你能帮我知道我需要做哪种配置吗?

public static Google.Apis.Drive.v2.Data.FileList ListFiles(DriveService service, FilesListOptionalParms optional = null)
        {
            try
            {

                if (service == null)
                    throw new ArgumentNullException("service");


                var request = service.Files.List();

                request = (FilesResource.ListRequest)SampleHelpers.ApplyOptionalParms(request, optional);

                return request.Execute();
            }
            catch (Exception ex)
            {
                throw new Exception("Request Files.List failed.", ex);
            }
        }

我称这个方法为每个文件我想在我的电脑上下载:

 FileList files_list = DriveListExample.ListFiles(service, null);
            if (files_list.Items.Count != 0)
            {
                foreach (var file in files_list.Items)
                {                        
                    DriveListExample.DownloadFile(service, file, DownloadDirectoryName);




                    Console.WriteLine("\"{0}\" ", file.Title + " downloaded completely!");


                }
            }

如果我可以访问每个文件的downloadUrl,我可以测试另一种下载方式。但它是null,这是我的下载方法:

public static void DownloadFile(DriveService服务,文件文件,字符串saveTo)     {

    var request = service.Files.Get(file.Id);
    var stream = new System.IO.MemoryStream();
    Console.WriteLine(file.FileExtension);


    request.MediaDownloader.ProgressChanged += (IDownloadProgress progress) =>
    {
        switch (progress.Status)
        {
            case DownloadStatus.Downloading:
                {
                    Console.WriteLine(progress.BytesDownloaded);
                    break;
                }
            case DownloadStatus.Completed:
                {
                    Console.WriteLine("Download complete.");
                    SaveStream(stream, saveTo);
                    break;
                }
            case DownloadStatus.Failed:
                {
                    Console.WriteLine("Download failed.");
                    break;
                }
        }
    };

    try
    {
        request.Download(stream);
    }
    catch (Exception ex)

    {
        Console.Write("Error: " + ex.Message);
    }

}

此过程中的下载状态为“失败”。 我也检查了范围,我发现使用这些行只允许我下载我在这个应用程序中创建的文件:

private static readonly string[] Scopes = new[] { DriveService.Scope.DriveFile, DriveService.Scope.Drive };

但我需要在列出所有文件后,我可以下载每个文件。

您能帮我解决一下这个解决方案或其他工作代码吗?

1 个答案:

答案 0 :(得分:1)

您需要使用有效的文件名并处理Google doc文件:

 public static void DownloadFile(DriveService service, Google.Apis.Drive.v2.Data.File file, string saveTo)
        {

            var request = service.Files.Get(file.Id);
            var stream = new System.IO.MemoryStream();

            // Add a handler which will be notified on progress changes.
            // It will notify on each chunk download and when the
            // download is completed or failed.
            request.MediaDownloader.ProgressChanged += (IDownloadProgress progress) =>
            {
                switch (progress.Status)
                {
                    case DownloadStatus.Downloading:
                        {
                            Console.WriteLine(progress.BytesDownloaded);
                            break;
                        }
                    case DownloadStatus.Completed:
                        {
                            Console.WriteLine("Download complete.");
                            SaveStream(stream, saveTo + @"/" + file.Title);
                            break;
                        }
                    case DownloadStatus.Failed:
                        {
                            if (file.ExportLinks.Any())
                                SaveStream(new HttpClient().GetStreamAsync(file.ExportLinks.FirstOrDefault().Value).Result, saveTo + @"/" + file.Title);
                            Console.WriteLine("Download failed.");
                            break;
                        }
                }
            };

            try
            {
                request.Download(stream);
            }
            catch (Exception ex)

            {
                Console.Write("Error: " + ex.Message);
            }

        }