Question

我正在从教科书上完成一项任务。我不能从同一个类中调出“poisonAttack”方法。如果有人能给我反馈，我将不胜感激。

public class PoisonMatango   extends Matango {
    PoisonMatango  pm = new PoisonMatango ('A');


    public PoisonMatango ( char suffix) {
        super(suffix);


    }
    // The method I am trying call.
    public void  poisonAttack(Hero h) {
        super.attack(h);
        int poisonCount = 5;
        if ( poisonCount >=0 ) {
            System.out.println("The enemy had spread poisonous pollons");
            int pollenDamage = h.hp / 5;
             h.hp-= pollenDamage;
            System.out.println("Hero has received " + pollenDamage + "damage from " );
            poisonCount --;
        }else
        {
            System.out.println("No additional attack were made since poisonCount= 0");
        }}

    }

Answer 1

您必须使用创建的Class对象'pm'来调用方法，并根据方法定义传递所需的参数。您的代码具有Hero类的对象类型参数

<强> pm.poisonAttack（小时）;

以下是上述代码的解决方案： -

//类对象在解决方案中用作参数公共阶级英雄{

int hp = 100;

}

//超级公共课Matango {

Hero a;

public Matango(Hero suffix) {
    this.a =suffix;
}

// Super Class Method 
public void attack(Hero h){
    System.out.println("\n\nHero hp var value::"+h.hp);
}

}

// PoisonMatango

public class PoisonMatango   extends Matango {


    public PoisonMatango ( Hero suffix) {
        super(suffix);


    }
    // The method I am trying call.
    public void  poisonAttack(Hero h) {
        super.attack(h);
        int poisonCount = 5;
        if ( poisonCount >=0 ) {
            System.out.println("The enemy had spread poisonous pollons\n");
            int pollenDamage = h.hp / 5;
             h.hp-= pollenDamage;
            System.out.println("Hero has received " + pollenDamage + "damage from \n" );
            poisonCount --;
        }else
        {
            System.out.println("No additional attack were made since poisonCount= 0 \n");
        }}


    public static void main(String args[])
    {
        // Create Object of Param class, this example passes object but we can pass simple data type as per method definition.
        Hero hr = new Hero();
        PoisonMatango  pm = new PoisonMatango (hr);

        pm.poisonAttack(hr);

    }

    }

如何用参数调用方法？（Java）

1 个答案: