如何使用随机数字让我的骰子游戏停止给我错误

Question

它一直在突出显示的区域给我语法错误，请有人告诉我为什么我得到它们。 this image shows you the code that i have used and highlighted areas where i get a syntax error

如果链接不起作用，则代码中没有突出显示的区域：

goes = 3
while True:
    import random
    die1 = 0
    die2 = 0
    die3 = 0
    die1 = str(random.randint(1,6))
    die2 = str(random.randint(1,6))
    die3 = str(random.randint(1,6))

    if die1 == die2 == die3:
        print(die1+die2+die3)

    if die1 == die2 not die3:
        print(die1+die2-die3)

    if die1 == die3 not die2:
        print(die1+die3-die2)

    if die2 == die3 not die1:
        print(die2+die3-die1)

    else:
        print(0)
    goes=goes-1
    if goes < 1:
        break

    print ([die1],[die2],[die3])

Answer 1

die1 == die2 not die3并不意味着什么。我认为你的意思是：

die1 == die2 and not (die1 == die3)

或更简单：

die1 == die2 and die1 != die3

由于我们已经检查过这三者是否相等，我们可以使用elif来避免以后的比较：

if die1 == die2 == die3:
    print(die1+die2+die3)
elif die1 == die2:
    print(die1+die2-die3)
elif die1 == die3:
    print(die1+die3-die2)
elif die2 == die3:
    print(die2+die3-die1)

因此，如果代码达到elif die1 == die2:，则表示die1 == die2 == die3为假。