这是代码,我有问题,当我想获得用户密钥(getPhone)我不能,导致获取null值我是编程中的新手。
LayoutInflater inflater = LayoutInflater.from(this);
View layout_pwd = inflater.inflate(R.layout.ganti_password_layout,null);
final MaterialEditText edtPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPassword);
final MaterialEditText edtNewPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaru);
final MaterialEditText edtRepeatPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaruUlang);
alertDialog.setView(layout_pwd);
//Button
alertDialog.setPositiveButton("GANTI", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
//Ganti Password Disini
final android.app.AlertDialog waitingDialog = new SpotsDialog(Home.this);
waitingDialog.show();
//cek password lama
if(edtPassword.getText().toString().equals(Common.currentUser.getPassword()))
{
//Cek Password Baru dan Ulang Password
if(edtNewPassword.getText().toString().equals(edtRepeatPassword.getText().toString()))
{
Map<String,Object> passwordUpdate = new HashMap<>();
passwordUpdate.put("password",edtNewPassword.getText().toString());
//Update
DatabaseReference user = FirebaseDatabase.getInstance().getReference("User");
user.child(Common.currentUser.getPhone())
.updateChildren(passwordUpdate)
.addOnCompleteListener(new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
}
});
}
else
{
waitingDialog.dismiss();
Toast.makeText(Home.this, "Pengulangan Password Tidak Sesuai", Toast.LENGTH_SHORT).show();
}
}
else
{
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Lama Salah", Toast.LENGTH_SHORT).show();
}
}
});
这是错误
过程:com.example.novaldi.sabilulunganlaykes,PID:15878 java.lang.NullPointerException:无法为child()中的参数'pathString'传递null 在com.google.firebase.database.DatabaseReference.child(未知来源:6) 在com.example.novaldi.sabilulunganlaykes.Home $ 4.onClick(Home.java:259) 在android.support.v7.app.AlertController $ ButtonHandler.handleMessage(AlertController.java:162) 在android.os.Handler.dispatchMessage(Handler.java:105) 在android.os.Looper.loop(Looper.java:164) 在android.app.ActivityThread.main(ActivityThread.java:6541) at java.lang.reflect.Method.invoke(Native Method) 在com.android.internal.os.Zygote $ MethodAndArgsCaller.run(Zygote.java:240) 在com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)
这是我的结构数据库 database structure
这是我的用户类
public User(){
}
public User(String nama, String password, String kodeKeamanan) {
Nama = nama;
Password = password;
IsStaff = "false";
this.KodeKeamanan = kodeKeamanan;
}
public String getKodeKeamanan() {
return KodeKeamanan;
}
public void setKodeKeamanan(String kodeKeamanan) {
KodeKeamanan = kodeKeamanan;
}
public String getPhone() {
return Phone;
}
public void setPhone(String phone) {
Phone = phone;
}
public String getIsStaff() {
return IsStaff;
}
public void setIsStaff(String isStaff) {
IsStaff = isStaff;
}
public String getNama() {
return Nama;
}
public void setNama(String nama) {
Nama = nama;
}
public String getPassword() {
return Password;
}
public void setPassword(String password) {
Password = password;
}
答案 0 :(得分:1)
此问题的存在是因为方法Common.currentUser.getPhone()
返回null。
要修复它,只需在null
方法调用之前添加简单的child()
测试。
像这样:
String phone = Common.currentUser.getPhone();
if (phone != null)
user.child(phone)
.updateChildren(passwordUpdate)
.addOnCompleteListener(new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
}
});
else {
// do something else here
}
或修改永远不会返回getPhone()
null
方法