我有以下代码从一个文件复制数据并粘贴到另一个文件中,有人可以帮我避免异常** FileSystemNotFoundException ** 谢谢你期待.............................................. ......................我添加了例外截图
package com.mod2.zipIn;
import java.io.*;
import java.net.*;
import java.nio.file.*;
import java.nio.file.FileSystem;
import java.util.*;
public class ZipIn {
public static void main(String[] args)
{
String[] data = {
"Line 1 ",
"Line 2 2 ",
"Line 3 3 3",
"Line 4 4 4 4",
"Line 5 5 5 5 5"
};
try (FileSystem zipFs = openZip(Paths.get("mydata.zip"))){
copyToZip(zipFs);
} catch (Exception e) {
System.out.println(e.getClass().getSimpleName() + " " + e.getMessage());
}
}
private static FileSystem openZip(Path zipPath) throws IOException, URISyntaxException {
Map<String, String> providerProps = new HashMap<>();
providerProps.put("Create", "True");
URI zipURI = new URI("jar:file", zipPath.toUri().getPath(), null);
FileSystem zipFs = FileSystems.newFileSystem(zipURI,providerProps);
return zipFs;
}
private static void copyToZip(FileSystem zipFs)throws IOException {
Path sourceFile = Paths.get("file1.txt");
Path destFile = zipFs.getPath("\file1Copied.txt");
Files.copy(sourceFile, destFile, StandardCopyOption.REPLACE_EXISTING);
}
}
答案 0 :(得分:0)
你确定,Paths.get(&#34; mydata.zip&#34;)会返回文件的有效路径吗? (找不到文件?!)
抱歉,本来会把它写成评论,但目前我不允许