Question

我每天下午1:00都需要Oracle作业调度程序的帮助。我希望在该单个作业调度程序上执行两个查询。查询如

第一个是简单的删除查询。

delete from NEWS_NO_OF_VIEWS where TO_CHAR(MONTH_YEAR,'MM-YYYY') = 
                                                         TO_CHAR(SYSDATE,'MM-YYYY')

，第二个是插入查询

INSERT INTO NEWS_NO_OF_VIEWS(NEWS_TYPE, NO_OF_VIEWS, MONTH_YEAR)    
((SELECT 'Latest News' AS NEWS_TYPE,NVL(SUM(NO_OF_VIEWED),0) NO_OF_VIEWS,MONTH_YEAR FROM(
    SELECT NO_OF_VIEWED,TO_CHAR(CREATED_DATE,'MM-YYYY') AS MONTH_YEAR FROM NEWS_LATEST_UR

 UNION ALL
    SELECT NO_OF_VIEWED,TO_CHAR(CREATED_DATE,'MM-YYYY')  AS MONTH_YEAR FROM NEWS_LATEST_EN
) E WHERE MONTH_YEAR = TO_CHAR(SYSDATE,'MM-YYYY') GROUP BY MONTH_YEAR)

Answer 1

你需要做的就是创建一个程序＆＃34; give_some_proc_name＆＃34;把你的＆＃34; DELETE＆＃34;和＆＃34; INSERT＆＃34;该过程中的语句并提交如下，以便将来如果你想添加或修改语句，你将很容易。

create or replace procedure give_some_proc_name
as
begin
delete from NEWS_NO_OF_VIEWS where TO_CHAR(MONTH_YEAR,'MM-YYYY') = TO_CHAR(SYSDATE,'MM-YYYY');
INSERT INTO NEWS_NO_OF_VIEWS(NEWS_TYPE, NO_OF_VIEWS, MONTH_YEAR)    
((SELECT 'Latest News' AS NEWS_TYPE,NVL(SUM(NO_OF_VIEWED),0) NO_OF_VIEWS,MONTH_YEAR FROM(
    SELECT NO_OF_VIEWED,TO_CHAR(CREATED_DATE,'MM-YYYY') AS MONTH_YEAR FROM NEWS_LATEST_UR
 UNION ALL
    SELECT NO_OF_VIEWED,TO_CHAR(CREATED_DATE,'MM-YYYY')  AS MONTH_YEAR FROM NEWS_LATEST_EN
) E WHERE MONTH_YEAR = TO_CHAR(SYSDATE,'MM-YYYY') GROUP BY MONTH_YEAR);
commit;
end;

然后创建如下作业，从今天01:00 PM开始，每天下午01:00运行。在工作中，你的job_type将是＆＃34; STORE_PROCEDURE＆＃34;和工作行动将是＆＃34; NAME_OF_PROCEDURE＆＃34;即＆＃34; give_some_proc_name＆＃34;前缀模式名称为＆＃34;。＆＃34;分隔符如下。

BEGIN
  DBMS_SCHEDULER.create_job (
    job_name        => 'give_some_name_to_job',
    job_type        => 'STORED_PROCEDURE',
    job_action      => 'schema_name.give_some_proc_name',
    start_date      => to_date(to_char(sysdate,'DD-MON-YYYY')||' 13:00:00','DD-MON-YYYY HH24:MI:SS'),
    repeat_interval => 'freq=daily; byhour=13; byminute=0; bysecond=0;',
    enabled         => TRUE);
END;

Oracle作业调度程序每天执行一次特定时间，对该作业任务进行两次查询

1 个答案: