Question

这是我的第三个问题。我现在已经两次在堆栈溢出的情况下被投票离开了岛屿，所以我对发帖感到有些不确定。

有人可以告诉我以下代码有什么问题。

所以我在错误中引用了一个函数。也就是说，如果发生错误，则代码重新引用它输入的函数，它再次运行。但是，当我第二次运行它时，如果两个输入都是正确的（数字）输入，我发现函数没有返回值。

    #This is a program that is designed to calculate gross pay:

def main():
    payment = input2()
    print('Gross pay: $', format(payment, ',.2f'), sep='')

def input2():
    try:
        #we're first getting the number of hours that the user is working.

        hours = int(input("How manyu hours did you work?: "))

        pay_rate = int(input("Enter your hourly payrate here: "))

        #display the gross pay
        gross_pay = hours * pay_rate
        payment = gross_pay
        #display the gross pay:
    except ValueError:
        print('Error: Nope')
        input2()
        return payment

Answer 1

恕我直言，这不是一个很好的递归使用，一个简单的while循环可以做到：

def input2():
    while True:
        try:
            #we're first getting the number of hours that the user is working.
            hours = int(input("How manyu hours did you work?: "))
            pay_rate = int(input("Enter your hourly payrate here: "))

            #display the gross pay
            gross_pay = hours * pay_rate
            return gross_pay
        except ValueError:
            print('Error: Nope')

要修复递归调用，请执行以下操作：

def input2():
    try:
        #we're first getting the number of hours that the user is working. 
        hours = int(input("How manyu hours did you work?: "))
        pay_rate = int(input("Enter your hourly payrate here: "))

        #display the gross pay
        gross_pay = hours * pay_rate
    except ValueError:
        print('Error: Nope')
        gross_pay = input2()

    return gross_pay

Answer 2

根据您的缩进，该函数仅返回Except块中的任何内容。如果您在没有错误的情况下通过了所有尝试的内容，那么您将永远无法获得“退款”。

希望有所帮助。

Answer 3

修正了你的代码，你走了，

def main():
    payment = input2()
    print('Gross pay: $', format(payment), sep='')

def input2():
    try:
        #we're first getting the number of hours that the user is working.

        hours = int(input("How manyu hours did you work?: "))

        pay_rate = int(input("Enter your hourly payrate here: "))

        #display the gross pay
        gross_pay = hours * pay_rate

        #display the gross pay
        return gross_pay
    except ValueError
        print('Error: Nope')
        return input2()


main()

在获得正确输入时显示输出，

在输入错误时会显示此信息，

Python：使用错误

3 个答案: