我试图通过使用spring boot和JPA来显示来自数据库的数据,但它总是抛出这个错误
这是我的:applications.properties
ui.tableWidget->setSelectionBehavior( QAbstractItemView::SelectRows );
ui.tableWidget->selectRow( 2 );
这是我的实体:AppUser
# ===============================
# DATABASE
# ===============================
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.datasource.url=jdbc:mysql://localhost:3306/userapp
spring.datasource.username=root
spring.datasource.password=
server.port=9092
# ===============================
# JPA / HIBERNATE
# ===============================
spring.jpa.show-sql=true
spring.jpa.hibernate.ddl-auto=none
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.MySQL5Dialect
现在这是我的DAO,包含请求的方法findUserAccount():
package entity;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.persistence.UniqueConstraint;
@Entity
@Table(name = "App_User", //
uniqueConstraints = { //
@UniqueConstraint(name = "APP_USER_UK", columnNames = "User_Name") })
public class AppUser {
@Id
@GeneratedValue
@Column(name = "User_Id", nullable = false)
private Long userId;
@Column(name = "User_Name", length = 36, nullable = false)
private String userName;
@Column(name = "Encryted_Password", length = 128, nullable = false)
private String encrytedPassword;
@Column(name = "Enabled", length = 1, nullable = false)
private boolean enabled;
public Long getUserId() {
return userId;
}
public void setUserId(Long userId) {
this.userId = userId;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getEncrytedPassword() {
return encrytedPassword;
}
public void setEncrytedPassword(String encrytedPassword) {
this.encrytedPassword = encrytedPassword;
}
public boolean isEnabled() {
return enabled;
}
public void setEnabled(boolean enabled) {
this.enabled = enabled;
}
}
最后消息错误:
package dao;
import javax.persistence.EntityManager;
import javax.persistence.NoResultException;
import javax.persistence.Query;
import entity.AppUser;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;
@Repository
@Transactional
public class AppUserDAO {
@Autowired
private EntityManager entityManager;
public AppUser findUserAccount(String userName) {
try {
String sql = "Select e from " + AppUser.class.getName() + " e " //
+ " Where e.userName = :userName ";
Query query = entityManager.createQuery(sql, AppUser.class);
query.setParameter("userName", userName);
return (AppUser) query.getSingleResult();
} catch (NoResultException e) {
return null;
}
}
}
感谢您的帮助