如何将jsonb数组转换为记录

Question

给定一个对象数组，我们可以使用jsonb_to_recordset将其转换为记录集。

select * from jsonb_to_recordset($$[
  {"name": "name01", "age": 12},
  {"name": "name02", "age": 14},
  {"name": "name03", "age": 16},
  {"name": "name04", "age": 18}
]$$) as (name text, age int)


name   |age |
-------|----|
name01 |12  |
name02 |14  |
name03 |16  |
name04 |18  |

但是如果我们更喜欢数组数组形式的源数据呢？如何转换下面的查询以产生类似的结果？

select array['name', 'age']  "labels"
     , x.value               "values" 
from jsonb_array_elements($$[
  ["name01", 12],
  ["name02", 14],
  ["name03", 16],
  ["name04", 18]
]$$) x


labels     |values         |
-----------|---------------|
{name,age} |["name01", 12] |
{name,age} |["name02", 14] |
{name,age} |["name03", 16] |
{name,age} |["name04", 18] |

Answer 1

您可以使用->>：

select x.value->>0 AS name,
       x.value->>1 AS age     
from jsonb_array_elements($$[
  ["name01", 12],
  ["name02", 14],
  ["name03", 16],
  ["name04", 18]
]$$) x;

输出：

+--------+-----+
|  name  | age |
+--------+-----+
| name01 |  12 |
| name02 |  14 |
| name03 |  16 |
| name04 |  18 |
+--------+-----+

<强> DBFiddle Demo