Question

我堆叠了一个我无法实现的查询，并且没有弄清楚问题，

SELECT * FROM sites AS s
 INNER JOIN sites_authors AS s_aut ON s_aut.site_id = s.site_id
 INNER JOIN authors AS aut ON aut.author_id = s_aut.author_id
 INNER JOIN author_trans AS trans ON trans.lang_iso = aut.lang_iso

 LEFT JOIN (
  countries_authors AS c_aut
INNER JOIN zones AS z ON z.zone_id = c_aut.zone_id
    AND z.code = aut.code
INNER JOIN carriers_zones AS cz ON cz.zone_id = z.zone_id
    AND cz.site_id = s.site_id
INNER JOIN carriers AS cr ON cr.carrier_id = cz.carrier_id
    AND cr.active = 1
 )
 ON c_aut.lang_iso = trans.lang_iso

我得到的错误是'on clause'中的未知列'aut.code'

以及'on子句'中的未知列's.site_id'

但是，当我用具体值替换这些列时，不会发生错误。

它是php-mysql项目中的查询

Answer 1

You can use like this

SELECT * FROM sites AS s
 INNER JOIN sites_authors AS s_aut ON s_aut.site_id = s.site_id
 INNER JOIN authors AS aut ON aut.author_id = s_aut.author_id
 INNER JOIN author_trans AS trans ON trans.lang_iso = aut.lang_iso
 LEFT JOIN (
    SELECT * FROM countries_authors AS c_aut
    INNER JOIN zones AS z ON z.zone_id = c_aut.zone_id
    INNER JOIN carriers_zones AS cz ON cz.zone_id = z.zone_id
    INNER JOIN carriers AS cr ON cr.carrier_id = cz.carrier_id
    AND cr.active = 1
 ) t
 ON t.lang_iso = trans.lang_iso  AND t.code = aut.code  AND t.site_id = s.site_id;

SQL JOIN范围未知列

1 个答案: