Question

我编写了一个在两个分隔符之间提取字符串的函数。但是在某些文件中，这些分隔符会出现几次，所以我想提取所有这些分隔符。在我的实际功能中，它只提取它遇到的第一个然后退出。

我该如何解决？

def extraction_error_CF(file): 

    f=open(file,'r')
    file=f.read()
    f.close()
    start = file.find('Error validating') #1st delimiter
    end = file.find('</SPAN><BR>', start) # 2nd delimiter
    if start!=-1 and end!=-1:             #If these two delimiters are present...
        return(file[start:end])
    else:
        return""

Answer 1

对于HTML / XML，您应该完全使用像BeautifulSoup这样的强大模块，但如果您真的只想要两个分隔符之间的内容，您可以使用相同的功能，但将结果添加到列表中（例如）然后您可以将其打印出来

def extraction_error_CF(file): 

    f=open(file,'r')
    file=f.read()
    f.close()

    # Patterns
    first = "Error validating"
    second = "</span><br>"

    # For all the matches
    results = []

    # Iterate the whole file
    start = file.find(first)
    end = file.find(second)
    while start != -1 and end != -1:
        # Add everything between the patterns
        # but not including the patterns
        results.append(file[start+len(first):end])
        # Removing the text that already passed
        file = file[end+len(second):]

        start = file.find(first)
        end = file.find(second)

    # Return the content of the list as a string
    if len(results) != 0:
        return "".join(r for r in results)
    else:
        return None

print(extraction_error_CF("test"))

Answer 2

import re

def extraction_error_CF(file): # Get error from CF upload 
    f=open(file,'r')
    file=f.read()
    f.close()
    start = re.findall('Error validating(.*)</SPAN><BR>',file)
    if start != -1:
        return start
    else:
        return""

这就是我的所作所为，感谢所有人！

提取分隔符之间的所有字符串

2 个答案: