Question

我的数据库中有一个名为faculty的表。我从可以看到院系名称的地方做了一个下拉列表。我还尝试按下一个按钮来删除当前选中的元素。但它所做的一切，就是将所选项目更改为另一项，而不是从数据库中删除教师。我是PHP的新手，有点帮助吗？

＆＃13;

    <?php
    $query = "SELECT name, faculty_id FROM faculty ORDER BY name ASC";
    $result = mysqli_query($con, $query) or die(mysqli_error());
    ?>

    <select name="categories">
        <?php
        while ($row = mysqli_fetch_array($result)) {
            echo "<option value='" . $row['faculty_id'] . "'>" . $row['name'] . "</option>";
            $row = $row['faculty_id'];
        }
        ?>
    </select>
    <?php
    if (isset($_POST['delete_faculty'])) {
        $sql = "DELETE FROM faculty WHERE faculty_id = $row";

        $result = mysqli_query($con, $sql);
    }
    ?>
    <form action="admin" method="post">
        <button type="submit" name="delete_faculty">Delete</button>
    </form>

＆＃13;

Answer 1

<?php
        $query = "SELECT name, faculty_id FROM faculty ORDER BY name ASC";
        $result = mysqli_query($con, $query) or die(mysqli_error());
        ?>
       <form action="#" method="post">
        <select name="categories">
            <?php
            while ($row = mysqli_fetch_array($result)) {
                echo "<option value='" . $row['faculty_id'] . "'>" . $row['name'] . "</option>";
                $row = $row['faculty_id'];
            }
            ?>
        </select>
            <input type="submit" name="delete_faculty" value="Delete">
        </form>
        <?php
        if (isset($_POST['delete_faculty'])) {
            $cato = $_POST['categories'];
            $sql = "DELETE FROM faculty WHERE faculty_id = $cato";

            $result = mysqli_query($con, $sql);
            header("Refresh:0");
        }
        ?>

Answer 2

您忘记在delete查询中使用正确的行ID。这应该是诀窍：

$facultyId = (int)$_POST['delete_faculty'];
$sql = "DELETE FROM faculty WHERE faculty_id = " . $facultyId;

此外，您应该查看准备好的陈述。他们会帮助您避免SQL注入

如何从php中的droplist中正确删除记录？

2 个答案: