我编写了一个SQL函数,用于将SQL中的日期时间值转换为更友好的“n Hours Ago”或“n Days Ago”等类型的消息。我想知道是否有更好的方法来做到这一点。
(是的,我知道“不要在SQL中这样做”,但出于设计原因,我必须这样做)。
这是我写的函数:
CREATE FUNCTION dbo.GetFriendlyDateTimeValue
(
@CompareDate DateTime
)
RETURNS nvarchar(48)
AS
BEGIN
DECLARE @Now DateTime
DECLARE @Hours int
DECLARE @Suff nvarchar(256)
DECLARE @Found bit
SET @Found = 0
SET @Now = getDate()
SET @Hours = DATEDIFF(MI, @CompareDate, @Now)/60
IF @Hours <= 1
BEGIN
SET @Suff = 'Just Now'
SET @Found = 1
RETURN @Suff
END
IF @Hours < 24
BEGIN
SET @Suff = ' Hours Ago'
SET @Found = 1
END
IF @Hours >= 8760 AND @Found = 0
BEGIN
SET @Hours = @Hours / 8760
SET @Suff = ' Years Ago'
SET @Found = 1
END
IF @Hours >= 720 AND @Found = 0
BEGIN
SET @Hours = @Hours / 720
SET @Suff = ' Months Ago'
SET @Found = 1
END
IF @Hours >= 168 AND @Found = 0
BEGIN
SET @Hours = @Hours / 168
SET @Suff = ' Weeks Ago'
SET @Found = 1
END
IF @Hours >= 24 AND @Found = 0
BEGIN
SET @Hours = @Hours / 24
SET @Suff = ' Days Ago'
SET @Found = 1
END
RETURN Convert(nvarchar, @Hours) + @Suff
END
答案 0 :(得分:7)
正如你所说,我可能不会在SQL中这样做,但是作为思考练习有一个MySQL实现:
CASE
WHEN compare_date between date_sub(now(), INTERVAL 60 minute) and now()
THEN concat(minute(TIMEDIFF(now(), compare_date)), ' minutes ago')
WHEN datediff(now(), compare_date) = 1
THEN 'Yesterday'
WHEN compare_date between date_sub(now(), INTERVAL 24 hour) and now()
THEN concat(hour(TIMEDIFF(NOW(), compare_date)), ' hours ago')
ELSE concat(datediff(now(), compare_date),' days ago')
END
基于MySQL Date and Time手册页上的类似样本
答案 1 :(得分:3)
在Oracle中:
select
CC.MOD_DATETIME,
'Last modified ' ||
case when (sysdate - cc.mod_datetime) < 1
then round((sysdate - CC.MOD_DATETIME)*24) || ' hours ago'
when (sysdate - CC.MOD_DATETIME) between 1 and 7
then round(sysdate-CC.MOD_DATETIME) || ' days ago'
when (sysdate - CC.MOD_DATETIME) between 8 and 365
then round((sysdate - CC.MOD_DATETIME) / 7) || ' weeks ago'
when (sysdate - CC.MOD_DATETIME) > 365
then round((sysdate - CC.MOD_DATETIME) / 365) || ' years ago'
end
from
customer_catalog CC
答案 2 :(得分:2)
我的尝试 - 这是针对MS SQL的。它支持'前'和'从现在',复数,它不使用舍入或约会,但截断 - 约会在8/30和9/1之间给出1个月的差异,这可能不是你想要的。舍入在9/1和9/16之间提供1个月的差异。再一次,可能不是你想要的。
CREATE FUNCTION dbo.GetFriendlyDateTimeValue( @CompareDate DATETIME ) RETURNS NVARCHAR(48) AS BEGIN
declare @s nvarchar(48)
set @s='Now'
select top 1 @s=convert(nvarchar,abs(n))+' '+s+case when abs(n)>1 then 's' else '' end+case when n>0 then ' ago' else ' from now' end from (
select convert(int,(convert(float,(getdate()-@comparedate))*n)) as n, s from (
select 1/365 as n, 'Year' as s union all
select 1/30, 'Month' union all
select 1, 'Day' union all
select 7, 'Week' union all
select 24, 'Hour' union all
select 24*60, 'Minute' union all
select 24*60*60, 'Second'
) k
) j where abs(n)>0 order by abs(n)
return @s
END
答案 3 :(得分:1)
您的代码看起来很实用。至于更好的方式,那将是主观的。您可能想要查看此page,因为它处理SQL中的时间跨度。
答案 4 :(得分:1)
这个怎么样?您可以扩展此模式以执行“年”消息,并且您可以检查“1天”或“1小时”,因此它不会说“1天前”......
我喜欢SQL中的CASE语句。
drop function dbo.time_diff_message
GO
create function dbo.time_diff_message (
@input_date datetime
)
returns varchar(200)
as
begin
declare @msg varchar(200)
declare @hourdiff int
set @hourdiff = datediff(hour, @input_date, getdate())
set @msg = case when @hourdiff < 0 then ' from now' else ' ago' end
set @hourdiff = abs(@hourdiff)
set @msg = case when @hourdiff > 24 then convert(varchar, @hourdiff/24) + ' days' + @msg
else convert(varchar, @hourdiff) + ' hours' + @msg
end
return @msg
end
GO
select dbo.time_diff_message('Dec 7 1941')
答案 5 :(得分:1)
感谢上面发布的各种代码。
正如Hafthor指出的那样,原始代码与舍入有限制。我还发现他的代码被踢出的一些结果与我所期望的结果不符。星期五下午 - &gt;星期一早上会显示为“2天前”。我想我们都会在3天前打电话给我们,即使已经完成了3个完整的24小时。
所以我修改了代码(这是MS SQL)。免责声明:我是新手TSQL编码器,所以这很黑,但有效!!
我做了一些改写 - 例如任何长达2周的东西都以天为单位表示。超过2个月的任何事情都以数周表示。任何事情都是在几个月之内等等。看起来就像表达它的直观方式。
CREATE FUNCTION [dbo].[GetFriendlyDateTimeValue]( @CompareDate DATETIME ) RETURNS NVARCHAR(48) AS BEGIN
declare @s nvarchar(48)
set @s='Now'
select top 1 @s=convert(nvarchar,abs(n))+' '+s+case when abs(n)>1 then 's' else '' end+case when n>0 then ' ago' else ' from now' end from (
select convert(int,(convert(float,(getdate()-@comparedate))*n)) as n, s from (
select 1/365 as n, 'year' as s union all
select 1/30, 'month' union all
select 1/7, 'week' union all
select 1, 'day' union all
select 24, 'hour' union all
select 24*60, 'minute' union all
select 24*60*60, 'second'
) k
) j where abs(n)>0 order by abs(n)
if @s like '%days%'
BEGIN
-- if over 2 months ago then express in months
IF convert(nvarchar,DATEDIFF(MM, @CompareDate, GETDATE())) >= 2
BEGIN
select @s = convert(nvarchar,DATEDIFF(MM, @CompareDate, GETDATE())) + ' months ago'
END
-- if over 2 weeks ago then express in weeks, otherwise express as days
ELSE IF convert(nvarchar,DATEDIFF(DD, @CompareDate, GETDATE())) >= 14
BEGIN
select @s = convert(nvarchar,DATEDIFF(WK, @CompareDate, GETDATE())) + ' weeks ago'
END
ELSE
select @s = convert(nvarchar,DATEDIFF(DD, @CompareDate, GETDATE())) + ' days ago'
END
return @s
END
答案 6 :(得分:0)
上面的帖子给了我一些好主意,所以这里是使用SQL Server 2012的任何人的另一个功能。
CREATE FUNCTION [dbo].[FN_TIME_ELAPSED]
(
@TIMESTAMP DATETIME
)
RETURNS VARCHAR(50)
AS
BEGIN
RETURN
(
SELECT TIME_ELAPSED =
CASE
WHEN @TIMESTAMP IS NULL THEN NULL
WHEN MINUTES_AGO < 60 THEN CONCAT(MINUTES_AGO, ' minutes ago')
WHEN HOURS_AGO < 24 THEN CONCAT(HOURS_AGO, ' hours ago')
WHEN DAYS_AGO < 365 THEN CONCAT(DAYS_AGO, ' days ago')
ELSE CONCAT(YEARS_AGO, ' years ago') END
FROM ( SELECT MINUTES_AGO = DATEDIFF(MINUTE, @TIMESTAMP, GETDATE()) ) TIMESPAN_MIN
CROSS APPLY ( SELECT HOURS_AGO = DATEDIFF(HOUR, @TIMESTAMP, GETDATE()) ) TIMESPAN_HOUR
CROSS APPLY ( SELECT DAYS_AGO = DATEDIFF(DAY, @TIMESTAMP, GETDATE()) ) TIMESPAN_DAY
CROSS APPLY ( SELECT YEARS_AGO = DATEDIFF(YEAR, @TIMESTAMP, GETDATE()) ) TIMESPAN_YEAR
)
END
GO
实施:
SELECT TIME_ELAPSED = DBO.FN_TIME_ELAPSED(AUDIT_TIMESTAMP)
FROM SOME_AUDIT_TABLE