Question

let obj=[
  {
    "type": "Bedroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test"
  },
  {
    "type": "Bedroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test1"
  },
  {
    "type": "Bedroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test"
  },
  {
    "type": "Bathroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test"
  },
  {
    "type": "Bathroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test"
  },
  {
    "type": "Bathroom",
    "int_input": 1,
    "enum_input": 0,
    "enum_select": "Yes",
    "description": "Test"
  }
]
//first take the type
let type_only=obj.map(o=>o.type);
type_only=Array.from(new Set(type_only));

let sum_obj={};
let arr=[];
//iterate types

{type_only.map((val,index) =>{
    // c is an object, append description only and not object
    // Also, check for blank description while appending
    sumobj = obj.reduce((c, v) => v.type === val ? {'description': (c.description ? c.description + ','+ v.description : v.description),'type':v.type} : c, 0)
    arr.push(sumobj);
    }
    )}

console.log(arr);
console.log(type_only);

我想迭代每个 div.reviews-summary ，但我没有进入下一个 p.reviews-title 和 li.rating__item rating__rated 标记，也计算 li.rating__item rating__rated ，以整数显示 li.rating__item rating__rated 。

<div class="reviews-summary__stats">
    <div class="reviews-summary">
        <p class="reviews-title">C</p>
        <ul class="rating">
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item "></li>
            <li class="rating__item "></li>
        </ul>
    </div>
    <div class="reviews-summary">
        <p class="reviews-title">C</p>
        <ul class="rating">
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item "></li>
            <li class="rating__item "></li>
        </ul>
    </div>
    <div class="reviews-summary">
        <p class="reviews-title">C</p>
        <ul class="rating">
            <li class="rating__item rating__rated"></li>
            <li class="rating__item rating__rated"></li>
            <li class="rating__item "></li>
            <li class="rating__item "></li>
        </ul>
    </div>     
</div>

我希望像这种类型的输出一样显示的阵（     [overalldata] =＆gt;排列         （             [a] =＆gt; 3
            [b] =＆gt; 4
            [c] =＆gt; 2
        ））并计算<?php include("simple_html_dom.php"); $obj = new simple_html_dom(); foreach ($obj->find('div[class=reviews-summary]') as $factor) { $item = $factor->find('p[class=reviews-title]')->plaintext; if(trim($item) == 'A') { $a = $factor->find('li[class=rating__item rating__rated]',0)->plaintext; } if(trim($item) == 'B') { $b = $factor->find('li[class=rating__item rating__rated]',0)->plaintext; } if(trim($item) == 'C') { $c = $factor->find('li[class=rating__item rating__rated]',0)->plaintext; } $final_array['overalldata'] = array ( 'a' => $a, // no of A have <li class="rating__item rating__rated"></li> 'b' => $b, 'c' => $c, ); } print_r($final_array); die; ?>它，并在列表中显示 li.rating__item rating__rated 的整数值

任何有任何想法的机构请帮忙解决。感谢

Answer 1

我做了一些更改，但包含了几个版本，因为它们都以不同的方式格式化数据。我认为主要问题是，当您使用find()时，这可能会返回找到的项目列表，因此在设置$a等时，您使用了第二个参数来挑选plaintext在第一项（使用,0）中，您在查找$item值时没有这样做。所以我已经在此次电话会议中添加了相同内容。

$final_array=array();
foreach ($obj->find('div[class=reviews-summary]') as $factor)
{
    $item = $factor->find('p[class=reviews-title]',0)->plaintext;
    if(trim($item) == 'A')
    {
        $final_array['overalldata']['a'] = $factor->find('li[class=rating__item rating__rated]',0)->plaintext;
    }
    if(trim($item) == 'B')
    {
        $final_array['overalldata']['b'] = $factor->find('li[class=rating__item rating__rated]',0)->plaintext;
    }
    if(trim($item) == 'C')
    {
        $final_array['overalldata']['c'] = $factor->find('li[class="rating__item rating__rated"]',0)->plaintext;
    }
}
print_r($final_array);

这给出了（带有您的样本数据）......

Array
(
    [overalldata] => Array
        (
            [c] => 
        )

)

...替代地

$final_array=array();
foreach ($obj->find('div[class=reviews-summary]') as $factor)
{
    $a = null;
    $b = null;
    $c = null;
    $item = trim($factor->find('p[class=reviews-title]',0)->plaintext);
    $factor = $factor->find('li[class=rating__item rating__rated]');
    $count = count($factor);
    if($item == 'A')
    {
        $a = $factor[0]->plaintext;
    }
    if($item == 'B')
    {
        $b = $factor[0]->plaintext;
    }
    if($item == 'C')
    {
        $c = $factor[0]->plaintext;
    }
    $final_array['overalldata'] = array
    (
        'a' => $a,
        'b' => $b,
        'c' => $c,
        'count' =>$count
    );
}
print_r($final_array);

稍微修改了一组测试数据......

Array
(
    [overalldata] => Array
        (
            [a] => 
            [b] => 
            [c] => Some content
        )

)

<强>更新

我已经更新了第二个例子，我已经将一些常用代码移到了主要部分。 $count只是<li class="rating__item rating__rated">项目的数量（我认为这是您的要求）。

PHP：Simple DOM Parser如何迭代html代码

1 个答案: