ListView调用`get_template_names`而不调用它

Question

我正在阅读ListView的Django源代码： django/list.py

class MultipleObjectTemplateResponseMixin(TemplateResponseMixin):
    template_name_suffix = '_list'
    def get_template_names(self):
       try:
            names = super().get_template_names()

class ListView(MultipleObjectTemplateResponseMixin, BaseListView):
    """
    Render some list of objects, set by `self.model` or `self.queryset`.
    `self.queryset` can actually be any iterable of items, not just a queryset.
    """

当我定义ListView时，template_name会自动分配

class IndexView(generic.ListView):
    pass

我认为MultipleObjectTemplateResponseMixin中的分配步骤应该是

class MultipleObjectTemplateResponseMixin(TemplateResponseMixin):
    template_name_suffix = '_list'
    def get_template_names(self):
       try:
            names = super().get_template_names()
            ....
    template_name = self.get_template_names()

如何调用get_template_names而不调用它？

Answer 1

在get_template_names类的render_to_response方法中调用

TemplateResponseMixin，该方法是MultipleObjectTemplateResponseMixin的超类。