当我运行以下查询时，我得到一个包含238＆＃34;礼物的单行结果。＆＃34;如何查询返回238 LINES以便我可以看到与EACH礼物相关的收入？我试图消除Group By然后它生气并说我的选择没有意义（错误：＆＃34;列＆＃39; campcode.campcode＆＃39;在选择列表中无效，因为它不是包含在聚合函数或GROUP BY子句中。＆＃34;）。
select
c2.campcode,
substring(s1.source,1,6) as Package,
p.descrip as Panel,
pc.packcode,
pc.descrip,
COUNT(m1.names_id) as Mailed,
SUM(case when s1.numbermail=0 then 0 else (s1.acost/s1.numbermail) end) as Cost,
COUNT(c1.camt) as Gifts,
SUM(c1.camt) as Income
from mailing m1
left join source s1 with (nolock) on m1.source_key=s1.source_key
left join campcode c2 with (nolock) on s1.camp_key=c2.camp_key
left join packcode pc with (nolock) on pc.pack_key=s1.pack_key
left join panelcode p with (nolock) on p.panel_key = s1.panel_key
left join contrib c1 with (nolock) on m1.source_key = c1.source_key and
m1.names_id = c1.names_id
and c1.moneytype <> -1
and c1.type <> 6
and c1.camt >0
where c2.campcode like '18D9Y'
and substring(s1.source,1,6) like '18D9YC'
and c1.cdate between '2017-09-01' and '2018-04-23'
group by
c2.campcode,
substring(s1.source,1,6),
p.descrip,
pc.packcode,
pc.descrip