Question

我有一个名为RESTORE.XML的XML文档它具有这些价值......

<EmployeeDetails>
  <EmployeeID>156824</EmployeeID>
  <EmployeeName>ALEX</EmployeeName>
  <EmployeeAge>29</EmployeeAge>
</EmployeeDetails>

从我的c＃应用程序中我想读取这三个值并将其存储在3个不同的变量中。

如何使用c＃？感谢。

Answer 1

这应该有效：

using System.Xml.Linq;
XDocument xdoc = XDocument.Load("RESTORE.XML");
xdoc.Descendants("EmployeeID").First().Value;
xdoc.Descendants("EmployeeName").First().Value;

Answer 2

试试这个：

            XElement xml = XElement.Parse(@"
<EmployeeDetails>
  <EmployeeID>156824</EmployeeID>
  <EmployeeName>ALEX</EmployeeName>
  <EmployeeAge>29</EmployeeAge>
</EmployeeDetails>");

            int EmployeeID = int.Parse(xml.Element("EmployeeID").Value);
            string EmployeeName = xml.Element("EmployeeName").Value;
            int EmployeeAge = int.Parse(xml.Element("EmployeeAge").Value);

但是用xml文件加载代替解析......

Answer 3

XmlDocument doc = new XmlDocument();
doc.Load("restore.xml" );
foreach (XmlNode nd in doc.DocumentElement.SelectNodes( "xml/entry" ))
{
...
}

Answer 4

假设在我们的示例中，我们有一个带有根节点Reports的xml，并且有嵌套的子节点Reports，我们需要遍历每个孩子

sample.xml

<?xml version="1.0" encoding="utf-8" ?>
<Reports>
  <Report>
    <Code>CP</Code>
    <RepeatStyle>Weekly</RepeatStyle>
  </Report>
  <Report>
    <Code>USS</Code>
    <Name>User Snapshot</Name>
    <RepeatStyle>Monthly</RepeatStyle>
  </Report>
  <Report>
    <Code>USS</Code>
    <Name>Failed Logon Report</Name>
    <RepeatStyle>Monthly</RepeatStyle>
  </Report>
  <Report>
    <Code>USS</Code>
    <Name>Failed Logon Report</Name>
    <RepeatStyle>Monthly</RepeatStyle>
  </Report>
</Reports>

在这里，我们可以利用System.Xml.XmlDocument来读取目标位置中提供的Xml文件，并使用System.Xml.XmlNodeList来拾取某些节点

XmlDocument serverDoc = new XmlDocument();
serverDoc.Load("sample.xml");
XmlNodeList xml = serverDoc.SelectNodes("Reports/Report");

foreach (XmlNode node in xml)
{
      var code = node.SelectSingleNode("Code").InnerText;
      var repeatStyle = node.SelectSingleNode("RepeatStyle").InnerText;
}

如何从XML文件中读取值

4 个答案: