我正在更新" Rooms / {pushId} / ins"使用Google Cloud功能从多个"门/ {MACaddress} / ins"中获取新的 In 数据。 该功能目前如下:
exports.updateRoomIns = functions.database.ref('/doors/{MACaddress}').onWrite((change, context) => {
const beforeData = change.before.val(); // data before the write (data of all the doors child nodes)
const afterData = change.after.val(); // data after the write (data of all the doors child nodes)
const roomPushKey = afterData.inRoom; // get the right room
const insbefore = beforeData.ins;
const insafter = afterData.ins; // get the after data of only the "ins" node
console.log(insafter);
if (insbefore != insafter) {
const updates = {};
" const updates = {}"创建一个空的对象(稍后)填充,并(稍后)更新" rooms / {roompushkey} / ins"节点...
我认为这个问题可能出现在"更新" const,因为每次函数运行时都会将此对象重新定义为整体...
代码继续......
updates['/rooms/' + roomPushKey + '/ins'] = insafter; // populate the "INS" object with the values taken from the "/doors/{MACaddress/ins"
return admin.database().ref().update(updates); // do the update
} else {
return
}
});
如果我只有一扇门,这将有效,但由于我有几个门有不同的Ins数据,每次我更新一个"门/ {MACaddress / Ins",整个"房间/ {pushId} / INS"取代上次更新门上的任何数据...我知道更新方法应该用于此目的,我有点想保留这个"更新"对象以后将数据扇出到其他路径。这可能吗?关于如何解决这个问题的任何建议?
这是我的数据结构:
root: {
doors: {
111111111111: {
MACaddress: "111111111111",
inRoom: "-LBMH_8KHf_N9CvLqhzU", // I will need this value for the clone's path
ins: {
// I am creating several "key: pair"s here, something like:
1525104151100: true,
1525104151183: true,
}
},
222222222222: {
MACaddress: "222222222222",
inRoom: "-LBMH_8KHf_N9CvLqhzU", // I will need this value for the clone's path
ins: {
// I am creating several "key: pair"s here, something like:
2525104157710: true,
2525104157711: true,
}
}
},
rooms: {
-LBMH_8KHf_N9CvLqhzU: {
ins: {
// I want the function to clone the same data here:
1525104151100: true,
1525104151183: true,
}
}
}
答案 0 :(得分:2)
根据我之前对相关问题(How to clone a node to another path based on a reference value from the initial path on Google Cloud Functions?)的回答,我将调整代码如下:
exports.updateRoom = functions.database.ref('/doors/{MACaddress}').onWrite((change, context) => {
const afterData = change.after.val(); // data after the write
const roomPushKey = afterData.inRoom;
const ins = afterData.ins;
const updates = {};
Object.keys(ins).forEach(key => {
updates['/rooms/' + roomPushKey + '/ins/' + key] = true;
});
return admin.database().ref().update(updates);
}).catch(error => {
console.log(error);
//+ other rerror treatment if necessary
});
换句话说,不是替换完整的ins
对象,而是在现有的ins节点中添加新的子节点。