我尝试调用云函数并传递一些数据。我的数据类型为Map<String, Object>，内部又有一些嵌套Map<String, Object>。试图用这个来调用我的函数时：
getHttpsCallable(function).call(data)...
我收到此错误：
Cloud Function Exception:
java.lang.IllegalArgumentException: Object cannot be encoded in JSON: [Ljava.util.Map;@42896770
at com.google.firebase.functions.Serializer.encode(Serializer.java:136)
at com.google.firebase.functions.Serializer.encode(Serializer.java:77)
at com.google.firebase.functions.FirebaseFunctions.call(FirebaseFunctions.java:255)
at com.google.firebase.functions.FirebaseFunctions.access$100(FirebaseFunctions.java:34)
at com.google.firebase.functions.FirebaseFunctions$2.then(FirebaseFunctions.java:233)
at com.google.firebase.functions.FirebaseFunctions$2.then(FirebaseFunctions.java:225)
at com.google.android.gms.tasks.zzd.run(Unknown Source)
at android.os.Handler.handleCallback(Handler.java:733)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:146)
at android.app.ActivityThread.main(ActivityThread.java:5653)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:515)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1291)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1107)
at dalvik.system.NativeStart.main(Native Method)
打印数据对象时，它看起来像这样：
{items=[Ljava.util.Map;@42896770, element1=OzNGHzHeq6av03hRmMJ6, time=Sun May 05 04:40:00 MEZ 3918}
我尝试了以下内容： 我尝试在数据对象中打包数组而不是Map。 =＆GT;没用。
我试图将自己的数据转换为json并发送给它，这也无效。
我做了以下的事情：
Gson gson = new Gson();
String dataJSON = gson.toJson(data);
在一个很好的格式化JSON中恢复：
{"items":[{"count":1,"itemId":"94To3bKnxoWzayLdy55I"},{"count":3,"itemId":"fkNtIUxbfg5GhLJy2Dma"},{"count":1,"itemId":"sDYTp7cpQTRfWuI6CSaK"},{"count":1,"itemId":"qGGl5U0qihHnMzhBMjyb","options":["2.0","1.0","1.1","0.0"]},{"count":1,"itemId":"qGGl5U0qihHnMzhBMjyb","options":["2.0","1.0","1.1","0.1"]},{"count":1,"itemId":"qGGl5U0qihHnMzhBMjyb","options":["2.0","1.0","1.1","0.2"]},{"count":1,"itemId":"qGGl5U0qihHnMzhBMjyb","options":["2.3","1.0","1.1","0.1"]}],"storeId":"OzNGHzHeq6av03hRmMJ6","pickupTime":"May 5, 3918 4:40:00 AM"}
但是我也尝试使用硬编码的JSON来调用我的函数，这个JSON也不起作用。
我无法弄清楚我做错了什么。有谁知道吗？
答案 0 :(得分：0)
我认为您应该从数据对象中创建并传递JSONObject。不是字符串或数据对象： 像这样：
Gson gson = new Gson();
String jsonString = gson.toJson(data);
JSONObject jsonObj = null;
try {
jsonObj = new JSONObject(jsonString);
} catch (JSONException e) {
e.printStackTrace();
}
，因为：
public Object encode(Object obj) {
if (obj != null && obj != JSONObject.NULL) {
JSONObject result;
if (obj instanceof Long) {
result = new JSONObject();
try {
result.put("@type", "type.googleapis.com/google.protobuf.Int64Value");
result.put("value", obj.toString());
return result;
} catch (JSONException var9) {
throw new RuntimeException("Error encoding Long.", var9);
}
} else if (obj instanceof Number) {
return obj;
} else if (obj instanceof String) {
return obj;
} else if (obj instanceof Boolean) {
return obj;
} else if (obj instanceof JSONObject) {
return obj;
} else if (obj instanceof JSONArray) {
return obj;
} else {
Object o;
String key;
Object value;
Iterator keys;
if (obj instanceof Map) {
result = new JSONObject();
Map<?, ?> m = (Map)obj;
keys = m.keySet().iterator();
while(keys.hasNext()) {
o = keys.next();
if (!(o instanceof String)) {
throw new IllegalArgumentException("Object keys must be strings.");
}
key = (String)o;
value = this.encode(m.get(o));
try {
result.put(key, value);
} catch (JSONException var10) {
throw new RuntimeException(var10);
}
}
return result;
} else {
JSONArray result;
if (obj instanceof List) {
result = new JSONArray();
List<?> l = (List)obj;
keys = l.iterator();
while(keys.hasNext()) {
o = keys.next();
result.put(this.encode(o));
}
return result;
} else {
JSONObject wrapped;
if (obj instanceof JSONObject) {
result = new JSONObject();
wrapped = (JSONObject)obj;
keys = wrapped.keys();
while(keys.hasNext()) {
String k = (String)keys.next();
if (!(k instanceof String)) {
throw new IllegalArgumentException("Object keys must be strings.");
}
key = k;
value = this.encode(wrapped.opt(k));
try {
result.put(key, value);
} catch (JSONException var11) {
throw new RuntimeException(var11);
}
}
return result;
} else if (!(obj instanceof JSONArray)) {
if (obj instanceof Date) {
String utc = this.dateFormat.format((Date)obj);
wrapped = new JSONObject();
try {
wrapped.put("@type", "type.googleapis.com/google.protobuf.Timestamp");
wrapped.put("value", utc);
return wrapped;
} catch (JSONException var12) {
throw new RuntimeException("Error encoding Date.", var12);
}
} else {
throw new IllegalArgumentException("Object cannot be encoded in JSON: " + obj);
}
} else {
result = new JSONArray();
JSONArray l = (JSONArray)obj;
for(int i = 0; i < l.length(); ++i) {
o = l.opt(i);
result.put(this.encode(o));
}
return result;
}
}
}
答案 1 :(得分：0)
通过org.json.JSONObject而不是com.google.gson.JsonObject很好。
您不需要在firebase函数上使用地图。