Question

我的json如下：

＆＃13;

[{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

＆＃13;

我想要使用第一个元素值（19）作为第二个元素的键的最短路径（而不是＆＃39; text＆＃39;）有多个元素，因此可以通过循环完成。然后删除第一个元素。

所以我想要输出如下（例如第一个元素[{＆＃34; id＆＃34;：19，＆＃34; text＆＃34;：＆＃34; AZ CLI 19/03/2015＆＃34; }]）：

＆＃13;

[{"19":"A-Z CLI 19/03/2015"}]

＆＃13;

Answer 1

您可以通过传递map函数作为参数来使用callback方法。

＆＃13;

let arr = [{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

arr = arr.map(function({id, text}){
    return { [id]: text };
});
console.log(arr);

＆＃13;

或只使用一个arrow功能。

＆＃13;

let arr = [{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

arr = arr.map(({id, text}) =>  ({[id]: text}));
console.log(arr);

＆＃13;

如何使用value元素作为第二个元素的键？

1 个答案: