Question

我有一张下面提到的列的表。我想获取以前的客户状态。一旦客户ID可以有多个条目

Customer_id   status     start_date    end_date   Active
1             Member      01-JAN-18    04-FEB-18   N
1             Explorist   05-FEB-18    30-APR-18   N
1             Globalist   01-MAY-18    31-DEC-99   Y

期望的输出

Customer _id     Previous_status   end_date
1                Explorist          30-APR-18

Answer 1

请使用QUALIFY关键字和ROW_NUMBER（）尝试以下查询：

SELECT a.* from table a 
QUALIFY ROW_NUMBER OVER(PARTITION BY customer_id order by start_date desc) = 2

Answer 2

以下查询应该有效。

SELECT * from (
SELECT a.*, 
ROW_NUMBER() over (partition by customer_id order by start_date desc) rn
 from table a ) 
where rn =2

Answer 3

您可以使用以下查询，我想这很简单，对我有用，

val input_json = {"name" : "john", "id" : 101}

Answer 4

请考虑以下问题：Select Nth Row From A Table In Oracle

在你的情况下，那将是：

select * from (select a.*, rownum rnum from (select * from <your table name> 
order by <start_date or end_date> desc) a where rownum <= 2) where rnum >= 2;

Answer 5

如果您使用的是Oracle DataBase，请使用 ROW_NUMBER（）功能尝试以下查询：我们认为表名是客户


    SELECT TEMP.CUSTOMER_ID
          ,TEMP.STATUS
          ,TEMP.START_DATE
          ,TEMP.END_DATE
          ,TEMP.ACTIVE 
          FROM(
            SELECT ROW_NUMBER() OVER (PARTITION BY CUSTOMER_ID ORDER BY CUSTOMER_ID ASC,START_DATE DESC) AS "ROW_NUM"
                  ,CUSTOMER_ID
                  ,STATUS
                  ,START_DATE
                  ,END_DATE
                  ,ACTIVE
                  FROM CUSTOMER) TEMP 
                      WHERE TEMP."ROW_NUM" = 2;

Sql查询从表中获取第二个最新条目

5 个答案: