Question

我有一张销售表

Date_s sales_man product qty
1-Jan-18   xx    01       30
1-Jan-18   xx    01       20
1-Jan-18   xy    01       20 
1-Feb-18   xz    02       10
5-Feb-18   xz    02       30
1-Feb-18   xx    01       10
1-Feb-18   xx    01       40
1-Mar-18   xy    03       20

我希望将以下输出数据格式设为

Product  sales_man  Jan  Feb   Mar
01       xx         50    10    0 
01       xy         20    0     0 
02       xx         0     0     0
02       xy         0     0     0
02       xz         0     0     0
03       xy         0     0     20

Answer 1

您可以使用聚合。像这样：

select product, salesperson,
       sum(case when extract(month from dates) = 1 then qty else 0 end) as jan,
       sum(case when extract(month from dates) = 2 then qty else 0 end) as feb
from t
group by product, salesperson;

这使用ANSI SQL日期函数，因为您的数据库标记不清楚。日期操作可能因数据库而异。

此外，在按月查看数据时，通常也要考虑年份（通过过滤或汇总年份）。

Answer 2

如果您可以更改日期格式，请参阅＆1; 1-Jan-18＆＃39;到＆＃39; 1-01-18＆＃39;，然后你可以在下面进行

检查sql小提琴

http://sqlfiddle.com/#!9/6d3824/2

如果您考虑以下日期格式＆＃39; 18年1月1日＆＃39 ;, ＆＃39; 18年1月1日＆＃39 ;, ＆＃39; 18年1月2日＆＃39 ;;

然后你可以做这个查询

derived

结果

select product, salesman,
       sum(case when extract(month from dates) = 1 then qty else 0 end) as jan,
       sum(case when extract(month from dates) = 2 then qty else 0 end) as feb
from sales
group by product, salesman;

整个月

http://sqlfiddle.com/#!9/6d3824/9

为所有人做这样的查询，

product salesman    jan feb
1       xx          30  0
1       xz          0   20
2       xy          10  0

结果将是

select product, salesman,
       sum(case when extract(month from dates) = 1 then qty else 0 end) as jan,
       sum(case when extract(month from dates) = 2 then qty else 0 end) as feb,
       sum(case when extract(month from dates) = 3 then qty else 0 end) as mar,
       sum(case when extract(month from dates) = 4 then qty else 0 end) as apr,
       sum(case when extract(month from dates) = 5 then qty else 0 end) as may,
       sum(case when extract(month from dates) = 6 then qty else 0 end) as jun,
       sum(case when extract(month from dates) = 7 then qty else 0 end) as jul,
       sum(case when extract(month from dates) = 8 then qty else 0 end) as aug,
       sum(case when extract(month from dates) = 9 then qty else 0 end) as sep,
       sum(case when extract(month from dates) = 10 then qty else 0 end) as oct,
       sum(case when extract(month from dates) = 11 then qty else 0 end) as nov,
       sum(case when extract(month from dates) = 12 then qty else 0 end) as dece
from sales
group by product, salesman;

Answer 3

如果我的问题正确，你可以尝试：

SELECT * into #TempTable FROM 
(select product, salesman, qty, FORMAT(Dates, 'MMM') as Months from sales
) AS s 
PIVOT 
(
   SUM(qty)
   FOR Months in (Jan, Feb)
) AS Pvt



select product, salesman, isnull(Jan, 0) as Jan, isnull(Feb, 0) as Feb from 
#TempTable order by product

drop table #TempTable

SQL我想得到以下输出

3 个答案: