Question

我有一个包含子数组的数组。我想对键相同的值求和，并将其放在一个列表中。

这是我的阵列：

$array =  array( array(x1=> 1, x2 => 3, y5 => 9),
                 array(x1=> 3, x4 => 1, y5 => 1),
                 array(x1=> 1, x8 => 5, a5 => 2),
                 array(x1=> 2, x10 => 3)
                );

我希望有一个像：

这样的数组

$newarray = array(x1=>7 , x2 => 3, x4=>1, x8=>5, x10=> 3, y5=>9, y5=>1, a5=>2));

尝试一下：

            foreach($array as $key => $values)
        {


            foreach($values as $n_k => $n_v)
            {   

                    $newarray [$n_k] += $n_v;


            }
        }

Answer 1

问题是即使未定义值，也要添加值。

您可以检查是否未设置并将值初始化为0

if ( !isset($newarray[$n_k]) ) $newarray[$n_k] = 0;

以下是完整的代码：

$array =  array( array('x1'=> 1, 'x2' => 3, 'y5' => 9), array('x1'=> 3, 'x4' => 1, 'y5' => 1), array('x1'=> 1, 'x8' => 5, 'a5' => 2), array('x1'=> 2, 'x10' => 3, 'b5' => 5));
$newarray = array();

foreach($array as $key => $values){
   foreach($values as $n_k => $n_v) {   
       if ( !isset($newarray[$n_k]) ) $newarray[$n_k] = 0;
       $newarray[$n_k] += $n_v;
   }
}

这将导致：

Array
(
    [x1] => 7
    [x2] => 3
    [y5] => 10
    [x4] => 1
    [x8] => 5
    [a5] => 2
    [x10] => 3
    [b5] => 5
)

Answer 2

这不是我的问题，但我发现这可以帮到你：

https://stackoverflow.com/a/14196064/9721446

您必须创建一个新数组，然后对于每个相等的keyid，您将要添加该值。像我认为的那样有些想法。如果没有帮助你，看看这篇文章，那也不是我的!!!!

Associative array, sum values of the same key

Answer 3

您可以先从数组中获取所有密钥，然后在array_column和array_sum中使用它来获得所需的输出。
如果阵列较大，这可能会带来更多好处。

$array =  array( array("x1" => 1, "x2" => 3, "y5" => 9),
                 array("x1" => 3, "x4" => 1, "y5" => 1),
                 array("x1" => 1, "x8" => 5, "a5" => 2),
                 array("x1" => 2, "x10" => 3, "b5" => 5)
                );

$keys = [];
// get all keys used in $array
foreach($array as $subarr){
     $keys = array_merge($keys, array_keys($subarr));
}
// $keys is now: 
// array (0 => 'x1', 1 => 'x2', 2 => 'y5', 3 => 'x1', 4 => 'x4', 5 => 'y5', 6 => 'x1', 7 => 'x8', 8 => 'a5', 9 => 'x1', 10 => 'x10', 11 => 'b5')

// loop only unique keys and sum the values
foreach(array_unique($keys) as $item){
    $res[$item] = array_sum(array_column($array, $item));
}
var_dump($res);

https://3v4l.org/WaqlG

Answer 4

＆＃13;

<?php
 $input =  array( array(x1=> 1, x2 => 3, y5 => 9),
 array(x1=> 3, x4 => 1, y5 => 1),
 array(x1=> 1, x8 => 5, a5 => 2),
 array(x1=> 2, x10 => 3)
);
 $final = array();
 array_walk_recursive($input, function($item, $key) use (&$final){
     $final[$key] = isset($final[$key]) ?  $item + $final[$key] : $item;
 });
  print_r($final);
  ?>

＆＃13;

php数组求和键，其中值相同

4 个答案: