Question

我在托管服务器上传时出现此错误，但在localhost中，网站状况良好，php版本设置为7.1。

警告：mysqli_query（）需要至少2个参数，第42行/storage/ssd3/410/5444410/public_html/update.php中给出的参数为1

警告：mysqli_fetch_array（）要求参数1为mysqli_result，在第43行的/storage/ssd3/410/5444410/public_html/update.php中给出null

代码：

<?php 
    $conn_db = mysqli_connect("localhost","user","password") or die();
    $sel_db = mysqli_select_db($conn_db, "dbname") or die();
    if(isset($_POST['update_password']))
    {
    $old_password=$_POST['old_password'];
    $new_password=$_POST['new_password'];
    $confirm_password=$_POST['confirm_password'];
    $chg_pwd=mysqli_query("SELECT * from member WHERE username='$user_check'"); //line 42
    $chg_pwd1=mysqli_fetch_array($chg_pwd); //line 43
    $data_pwd=$chg_pwd1['password'];
    if($data_pwd==$old_password){
    if($new_password==$confirm_password){
        $update_password=mysqli_query("UPDATE member SET password='$new_password' WHERE username='$user_check'");
        $viewpass = 'UPDATED SUCCESSFULLY!';
    }
    else{
        $errMsg = 'PASSWORD DOES NOT MATCH!';
    }
    }
    else
    {
    $errMsg2 = 'OLD PASSWORD IS WRONG!';
    }}
?>

我只是制作了一个简单的照片组合网站，我不知道如何处理这个问题。

Answer 1

试试这个

$chg_pwd=mysqli_query($conn_db,"SELECT * from member WHERE username='$user_check'"); 
$chg_pwd1=mysqli_fetch_array($chg_pwd, MYSQLI_ASSOC);

用于关联数组，或

$chg_pwd1=mysqli_fetch_array($chg_pwd, MYSQLI_NUM);

表示数字数组。

预期参数错误php

1 个答案: